Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

0=-(y^(2)-2y+x)

0=(y22y+x) 0=-\left(y^{2}-2 y+x\right)

Full solution

Q. 0=(y22y+x) 0=-\left(y^{2}-2 y+x\right)
  1. Identify equation: Identify the equation to be solved. The equation is 0=(y22y+x)0=-(y^{2}-2y+x).
  2. Rewrite without negative sign: Rewrite the equation without the negative sign by multiplying both sides by 1-1 to get a standard quadratic form. The equation becomes y22y+x=0y^{2}-2y+x=0.
  3. Recognize quadratic form: Recognize that the equation is a quadratic equation in the form of ay2+by+c=0ay^2 + by + c = 0, where a=1a=1, b=2b=-2, and c=xc=x.
  4. Use quadratic formula: To solve the quadratic equation, we can either factor it, complete the square, or use the quadratic formula. Since we do not have specific values for yy and xx, we will use the quadratic formula: y=b±b24ac2ay = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.
  5. Substitute values into formula: Substitute the values of aa, bb, and cc into the quadratic formula. This gives us y=(2)±(2)241x21.y = \frac{-(-2) \pm \sqrt{(-2)^2 - 4\cdot1\cdot x}}{2\cdot1}.
  6. Simplify equation: Simplify the equation by performing the operations inside the formula. This gives us y=2±44x2y = \frac{2 \pm \sqrt{4 - 4x}}{2}.
  7. Further simplify equation: Further simplify the equation by dividing the terms inside the square root as well as the 22 outside. This gives us y=1±1xy = 1 \pm \sqrt{1 - x}.

More problems from Find derivatives using the chain rule I