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0.30 P+0.25 G=57
A homeowner uses 
G hours of natural gas heat and 
P hours of heat from a pellet stove to heat her house one month, with a total of 57 therms of output. How many therms per hour does the pellet stove output?

0.30P+0.25G=57 0.30 P+0.25 G=57 \newlineA homeowner uses G G hours of natural gas heat and P P hours of heat from a pellet stove to heat her house one month, with a total of 5757 therms of output. How many therms per hour does the pellet stove output?

Full solution

Q. 0.30P+0.25G=57 0.30 P+0.25 G=57 \newlineA homeowner uses G G hours of natural gas heat and P P hours of heat from a pellet stove to heat her house one month, with a total of 5757 therms of output. How many therms per hour does the pellet stove output?
  1. Denoting the Output of the Pellet Stove: Let's denote the number of therms per hour the pellet stove outputs as PP. We are given the equation 0.30P+0.25G=570.30P + 0.25G = 57, where GG is the number of hours of natural gas heat used. We want to find the value of PP, which represents the therms per hour output of the pellet stove.
  2. Isolating PP in the Equation: To find PP, we need to isolate it on one side of the equation. However, we have two variables in the equation, PP and GG. Since we are only asked to find PP, we can treat GG as a constant or ignore it for now, as we are not asked to find its value.
  3. Rewriting the Equation: We can rewrite the equation to solve for PP: 0.30P=570.25G0.30P = 57 - 0.25G.
  4. Dividing Both Sides of the Equation: Now, we divide both sides of the equation by 0.300.30 to solve for PP: P=(570.25G)0.30P = \frac{(57 - 0.25G)}{0.30}.
  5. Expressing P in Terms of G: We notice that we cannot solve for P directly because we do not have the value of G. However, since we are only asked for the therms per hour output of the pellet stove (P), we can express P in terms of G: P=570.300.25G0.30 P = \frac{57}{0.30} - \frac{0.25G}{0.30} .
  6. Simplifying the Equation: Simplify the equation: P=19056G P = 190 - \frac{5}{6}G .
  7. Answering the Question Prompt: We realize that we cannot find a numerical value for PP without knowing GG. The question prompt asks for the therms per hour output of the pellet stove, which is represented by PP in the equation. Therefore, the answer to the question prompt is that the pellet stove outputs 0.300.30 therms per hour, as indicated by the coefficient of PP in the original equation.

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