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((u^(4)v^(-2)*uv^(2))^(4))/(2v^(3))

2525) (u4v2uv2)42v3 \frac{\left(u^{4} v^{-2} \cdot u v^{2}\right)^{4}}{2 v^{3}}

Full solution

Q. 2525) (u4v2uv2)42v3 \frac{\left(u^{4} v^{-2} \cdot u v^{2}\right)^{4}}{2 v^{3}}
  1. Simplify Inside Parentheses: First, simplify the expression inside the parentheses before raising it to the fourth power.\newline(u4v2uv2)=u4+1v2+2=u5v0=u5(u^{4}v^{-2}*uv^{2}) = u^{4+1}*v^{-2+2} = u^5*v^0 = u^5, since any number to the power of 00 is 11.
  2. Raise to Fourth Power: Now raise the simplified expression inside the parentheses to the fourth power. (u5)4=u5×4=u20 (u^5)^{4} = u^{5\times4} = u^{20} .
  3. Divide by Denominator: Next, divide the result by the denominator 2v32v^{3}. (u20)/(2v3)=(1/2)u20v3.(u^{20})/(2v^{3}) = (1/2)\cdot u^{20}\cdot v^{-3}.
  4. Final Simplified Form: Finally, write the expression in its simplified form.\newline(12)u20v(3)(\frac{1}{2})u^{20}v^{(-3)} is already in its simplest form.

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