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(n^(6)k^(14))^(5)
Which of the following is equivalent to the given expression?
Choose 1 answer:
(A) 
(n^(2)k^(5))^(3)
(B) 
(n^(3))^(10)(k^(2))^(7)
(C) 
(n^(15)k^(35))^(2)
(D) 
(n^(5))^(5)(k^(10))^(7)

(n6k14)5 \left(n^{6} k^{14}\right)^{5} \newlineWhich of the following is equivalent to the given expression?\newlineChoose 11 answer:\newline(A) (n2k5)3 \left(n^{2} k^{5}\right)^{3} \newline(B) (n3)10(k2)7 \left(n^{3}\right)^{10}\left(k^{2}\right)^{7} \newline(C) (n15k35)2 \left(n^{15} k^{35}\right)^{2} \newline(D) (n5)5(k10)7 \left(n^{5}\right)^{5}\left(k^{10}\right)^{7}

Full solution

Q. (n6k14)5 \left(n^{6} k^{14}\right)^{5} \newlineWhich of the following is equivalent to the given expression?\newlineChoose 11 answer:\newline(A) (n2k5)3 \left(n^{2} k^{5}\right)^{3} \newline(B) (n3)10(k2)7 \left(n^{3}\right)^{10}\left(k^{2}\right)^{7} \newline(C) (n15k35)2 \left(n^{15} k^{35}\right)^{2} \newline(D) (n5)5(k10)7 \left(n^{5}\right)^{5}\left(k^{10}\right)^{7}
  1. Apply power of power rule: Apply the power of a power rule.\newlineThe power of a power rule states that (am)n=a(mn)(a^m)^n = a^{(m*n)}. We will apply this rule to both n6n^6 and k14k^{14} raised to the 5th5^{\text{th}} power.
  2. Calculate new exponents: Calculate the new exponents for nn and kk.\newlineFor n6n^6 raised to the 5th5^{\text{th}} power, the new exponent is 6×5=306 \times 5 = 30.\newlineFor k14k^{14} raised to the 5th5^{\text{th}} power, the new exponent is 14×5=7014 \times 5 = 70.\newlineSo, (n6k14)5=n30k70(n^{6}k^{14})^{5} = n^{30}k^{70}.
  3. Compare with given options: Compare the result with the given options.\newlineWe have n30k70n^{30}k^{70}. Now we need to check which option is equivalent to this expression.\newlineOption (A) (n2k5)3(n^{2}k^{5})^{3} would give us n23k53=n6k15n^{2\cdot 3}k^{5\cdot 3} = n^{6}k^{15}, which is not equivalent.\newlineOption (B) (n3)10(k2)7(n^{3})^{10}(k^{2})^{7} would give us n310k27=n30k14n^{3\cdot 10}k^{2\cdot 7} = n^{30}k^{14}, which is also not equivalent.\newlineOption (C) (n15k35)2(n^{15}k^{35})^{2} would give us n152k352=n30k70n^{15\cdot 2}k^{35\cdot 2} = n^{30}k^{70}, which is equivalent to our expression.\newlineOption (D) (n5)5(k10)7(n^{5})^{5}(k^{10})^{7} would give us n55k107=n25k70n^{5\cdot 5}k^{10\cdot 7} = n^{25}k^{70}, which is not equivalent.\newlineTherefore, the correct answer is Option (C).