{:[g(x)=sqrt(2x+5)],[n(x)=(5x-1)/(x+2)]:} n(g(x))=?

Substitute Functions: To find the composition of the functions n(x) and g(x), denoted as n(g(x)), we need to substitute the function g(x) into the function n(x) wherever there is an x in n(x).Write Functions: First, let's write down the functions again for clarity: g(x) = sqrt(2x + 5) n(x) = (5x - 1) / (x + 2)Substitute g(x): Now, we substitute g(x) into n(x). This means every x in n(x) will be replaced with sqrt(2x + 5): n(g(x)) = (5 * sqrt(2x + 5) - 1) / (sqrt(2x + 5) + 2)Final Composition: We have successfully found the composition of the functions n(x) and g(x). There is no further simplification that can be done without specific values for x.

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{:[g(x)=sqrt(2x+5)],[n(x)=(5x-1)/(x+2)]:}

n(g(x))=?

$\begin{array}{r}g(x)=\sqrt{2 x+5} \\ n(x)=\frac{5 x-1}{x+2}\end{array}$ $\newline$ $n(g(x))=?$

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Algebra 2

Simplify variable expressions using properties

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\begin{array}{r}g(x)=\sqrt{2 x+5} \\ n(x)=\frac{5 x-1}{x+2}\end{array}

\newline

n(g(x))=?

Substitute Functions: To find the composition of the functions $n(x)$ and $g(x)$ , denoted as $n(g(x))$ , we need to substitute the function $g(x)$ into the function $n(x)$ wherever there is an $x$ in $n(x)$ .
Write Functions: First, let's write down the functions again for clarity: $\newline$ $g(x) = \sqrt{2x + 5}$ $\newline$ $n(x) = \frac{5x - 1}{x + 2}$
Substitute $g(x)$ : Now, we substitute $g(x)$ into $n(x)$ . This means every $x$ in $n(x)$ will be replaced with $\sqrt{2x + 5}$ : $n(g(x)) = \frac{5 \cdot \sqrt{2x + 5} - 1}{\sqrt{2x + 5} + 2}$
Final Composition: We have successfully found the composition of the functions $n(x)$ and $g(x)$ . There is no further simplification that can be done without specific values for $x$ .