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Find (fg)(0)(f \circ g)(0). f(x)=x+6f(x) = x + 6, g(x)=4xg(x) = 4x

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Q. Find (fg)(0)(f \circ g)(0). f(x)=x+6f(x) = x + 6, g(x)=4xg(x) = 4x
  1. Understand Composition of Functions: Understand the composition of functions. The composition of two functions ff and gg, denoted as (f@g)(x)(f@g)(x), means that we first apply gg to xx, and then apply ff to the result of g(x)g(x). So, (f@g)(x)=f(g(x))(f@g)(x) = f(g(x)).
  2. Find g(0)g(0): Find g(0)g(0). We are given g(x)=4xg(x) = 4x. To find g(0)g(0), we substitute xx with 00. g(0)=4×0=0g(0) = 4 \times 0 = 0.
  3. Find f(g(0))f(g(0)): Find f(g(0))f(g(0)). Now that we know g(0)=0g(0) = 0, we need to find f(0)f(0). We are given f(x)=x+6f(x) = x + 6. So, we substitute xx with 00. f(0)=0+6=6f(0) = 0 + 6 = 6.
  4. Find (f@g)(0)(f@g)(0): Find (f@g)(0)(f@g)(0).\newlineSince we have found that g(0)=0g(0) = 0 and f(0)=6f(0) = 6, we can now find (f@g)(0)(f@g)(0) which is f(g(0))f(g(0)).\newline(f@g)(0)=f(0)=6(f@g)(0) = f(0) = 6.

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