Identify Function and Rule: Identify the function and the rule to use for differentiation.We have a function of the form v(x)u(x), where u(x)=−x2+7x−10 and v(x)=6x+11. To find the derivative of a quotient, we use the quotient rule, which states that (vu)′=v2v∗u′−u∗v′.
Differentiate Numerator: Differentiate the numerator u(x)=−x2+7x−10. Using the power rule, the derivative of u(x) with respect to x is u′(x)=dxd(−x2)+dxd(7x)−dxd(10)=−2x+7.
Differentiate Denominator: Differentiate the denominator v(x)=6x+11. Using the power rule and the constant rule, the derivative of v(x) with respect to x is v′(x)=dxd(6x)+dxd(11)=6.
Apply Quotient Rule: Apply the quotient rule.Now we apply the quotient rule: f′(x)=v2v∗u′−u∗v′.Substituting the derivatives we found in Steps 2 and 3, we get:f′(x)=(6x+11)2(6x+11)(−2x+7)−(−x2+7x−10)6.
Expand and Simplify: Expand the numerator and simplify.Expanding the numerator, we get:f′(x)=(−12x2+42x+6x−77−(−6x2+42x−60))/(6x+11)2.Simplifying the numerator, we get:f′(x)=(−12x2+48x−77+6x2−42x+60)/(6x+11)2.f′(x)=(−6x2+6x−17)/(6x+11)2.
Check for Simplifications: Check for any possible simplifications. The numerator and the denominator do not have any common factors, so this is the simplified form of the derivative.
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