Identify u and v: We need to find the derivative of the function (3x−2)6x with respect to x. This is a quotient, so we will use the quotient rule which states that dxd(vu)=v2v(u′)−u(v′), where u is the numerator and v is the denominator.
Find u′ and v′: Let's identify u and v for our function. Here, u=x and v=(3x−2)6. We will need to find the derivatives of u and v, denoted as u′ and v′ respectively.
Derivative of u: First, we find the derivative of u with respect to x. Since u=x, the derivative u′=dxd(x)=1.
Derivative of v: Next, we find the derivative of v with respect to x. Since v=(3x−2)6, we will use the chain rule. The chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. So, v′=dxd((3x−2)6)=6∗(3x−2)5∗dxd(3x−2)=6∗(3x−2)5∗3.
Apply quotient rule: Now we apply the quotient rule. The derivative of our function with respect to x is given by:(dxdy)=((3x−2)6)2(3x−2)6⋅(dxd)(x)−x⋅(dxd)((3x−2)6)Substituting the derivatives we found, we get:(dxdy)=((3x−2)12)(3x−2)6⋅1−x⋅6⋅(3x−2)5⋅3
Simplify expression: Simplify the expression by distributing and combining like terms: (dxdy)=(3x−2)12(3x−2)6−18x(3x−2)5
Factor out: We can factor out a (3x−2)5 from the numerator to simplify the expression further:(dy/dx)=((3x−2)12)(3x−2)5⋅(1−18x)
Cancel out: Now we can cancel out (3x−2)5 from the numerator and denominator: (dy/dx)=(3x−2)71−18x
Final derivative: We have found the derivative of the function (3x−2)6x with respect to x, which is (3x−2)71−18x.
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