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question: \begin{aligned} \text{A. }&(55b2-2)^22+44=2525b^2220-20b \ \text{B. }&(22x^22+y^22)(22x^22-y^22)=44x^22-y^22 \end{aligned}

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Q. question: \begin{aligned} \text{A. }&(55b2-2)^22+44=2525b^2220-20b \ \text{B. }&(22x^22+y^22)(22x^22-y^22)=44x^22-y^22 \end{aligned}
  1. Expand left side of A: Expand the left side of equation A.\newline(5b2)2+4=25b220b+4 (5b-2)^2 + 4 = 25b^2 - 20b + 4
  2. Simplify left side of A: Simplify the left side of equation A.\newline25b220b+4=25b220b 25b^2 - 20b + 4 = 25b^2 - 20b
  3. Subtract from both sides of A: Subtract 25b220b25b^2 - 20b from both sides of equation A.\newline4=0 4 = 0
  4. Check errors in A: Check for errors in equation A. The equation 4=04 = 0 is not possible, so there is no solution for A.
  5. Expand left side of B: Expand the left side of equation B.\newline(2x2+y2)(2x2y2)=4x4y4 (2x^2 + y^2)(2x^2 - y^2) = 4x^4 - y^4
  6. Simplify right side of B: Simplify the right side of equation B.\newline4x4y4=4x2y2 4x^4 - y^4 = 4x^2 - y^2
  7. Check errors in B: Check for errors in equation B. The simplified form 4x4y4=4x2y24x^4 - y^4 = 4x^2 - y^2 does not match the original equation, so there is no solution for B.

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