Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

/alentina is trying to decide whether to join her school's swim team. During the summer, eam practices 4 days per week. Each of those days, they practice for 3 hours in the mort and practice again in the afternoon. They practice for a total of 20 hours each week.
Which equation can you use to find 
h, the length of each afternoon practice in hours?

{:[3(h+4)=20],[4(h+3)=20]:}

3h+4=20

4h+3=20
How long is each afternoon practice?

Valentina is trying to decide whether to join her school's swim team. During the summer, the team practices 44 days per week. Each of those days, they practice for 33 hours in the morning and practice again in the afternoon. They practice for a total of 2020 hours each week.\newlineWhich equation can you use to find hh, the length of each afternoon practice in hours?\newline3(h+4)=203(h+4)=20\newline4(h+3)=204(h+3)=20\newline3h+4=203h+4=20\newline4h+3=204h+3=20\newlineHow long is each afternoon practice?

Full solution

Q. Valentina is trying to decide whether to join her school's swim team. During the summer, the team practices 44 days per week. Each of those days, they practice for 33 hours in the morning and practice again in the afternoon. They practice for a total of 2020 hours each week.\newlineWhich equation can you use to find hh, the length of each afternoon practice in hours?\newline3(h+4)=203(h+4)=20\newline4(h+3)=204(h+3)=20\newline3h+4=203h+4=20\newline4h+3=204h+3=20\newlineHow long is each afternoon practice?
  1. Question Prompt: Question Prompt: How long is each afternoon practice for Valentina if she joins the swim team?
  2. Identify Equation: Identify the correct equation to use. Since the total weekly practice hours are 2020, and they practice 44 days a week, the equation that correctly represents the situation is 4(h+3)=204(h+3)=20, where hh is the length of each afternoon practice.
  3. Solve Equation: Solve the equation 4(h+3)=204(h+3)=20. First, divide both sides by 44 to isolate (h+3)(h+3). \newline4(h+3)4=204\frac{4(h+3)}{4} = \frac{20}{4}\newlineh+3=5h+3 = 5
  4. Subtract to Find hh: Subtract 33 from both sides to solve for hh.h+33=53h+3-3 = 5-3h=2h = 2

More problems from Solve one-step and two-step linear equations: word problems