Q. Find the limit as
x approaches 10 of limxβ10βxβ10x2β100β
Substitution Check: First, let's try to directly substitute the value x=10 into the function to see if it results in an indeterminate form.Substitute x=10 into (x2β100)/(xβ10):(102β100)/(10β10)=(100β100)/(10β10)=0/0.This is an indeterminate form, so we cannot directly evaluate the limit by substitution.
Simplify Expression: Since we have an indeterminate form of 0/0, we should try to simplify the expression to eliminate the common factor in the numerator and the denominator.Factor the numerator:x2β100=(x+10)(xβ10).Now the function becomes xβ10(x+10)(xβ10)β.
Cancel Common Factor: Next, we cancel out the common factor (xβ10) in the numerator and the denominator, as long as x is not equal to 10 (which it isn't, since we are taking a limit as x approaches 10, not evaluating at x=10).The function simplifies to:(x+10) when xξ =10.
Final Substitution: Now that we have simplified the function, we can directly substitute x=10 to find the limit.Substitute x=10 into (x+10):10+10=20.
Limit Calculation: The limit as x approaches 10 of the function xβ10x2β100β is 20.
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