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Find the limit as 
x approaches 10 of 
lim_(x rarr10)(x^(2)-100)/(x-10)

Find the limit as π‘₯π‘₯ approaches 10 of lim⁑xβ†’10x2βˆ’100xβˆ’10\lim_{x \to 10}\frac{x^{2}-100}{x-10}

Full solution

Q. Find the limit as π‘₯π‘₯ approaches 10 of lim⁑xβ†’10x2βˆ’100xβˆ’10\lim_{x \to 10}\frac{x^{2}-100}{x-10}
  1. Substitution Check: First, let's try to directly substitute the value x=10x = 10 into the function to see if it results in an indeterminate form.\newlineSubstitute x=10x = 10 into (x2βˆ’100)/(xβˆ’10)(x^2 - 100)/(x - 10):\newline(102βˆ’100)/(10βˆ’10)=(100βˆ’100)/(10βˆ’10)=0/0(10^2 - 100)/(10 - 10) = (100 - 100)/(10 - 10) = 0/0.\newlineThis is an indeterminate form, so we cannot directly evaluate the limit by substitution.
  2. Simplify Expression: Since we have an indeterminate form of 0/00/0, we should try to simplify the expression to eliminate the common factor in the numerator and the denominator.\newlineFactor the numerator:\newlinex2βˆ’100=(x+10)(xβˆ’10)x^2 - 100 = (x + 10)(x - 10).\newlineNow the function becomes (x+10)(xβˆ’10)xβˆ’10\frac{(x + 10)(x - 10)}{x - 10}.
  3. Cancel Common Factor: Next, we cancel out the common factor (xβˆ’10)(x - 10) in the numerator and the denominator, as long as xx is not equal to 1010 (which it isn't, since we are taking a limit as xx approaches 1010, not evaluating at x=10x = 10).\newlineThe function simplifies to:\newline(x+10)(x + 10) when xβ‰ 10x \neq 10.
  4. Final Substitution: Now that we have simplified the function, we can directly substitute x=10x = 10 to find the limit.\newlineSubstitute x=10x = 10 into (x+10)(x + 10):\newline10+10=2010 + 10 = 20.
  5. Limit Calculation: The limit as xx approaches 1010 of the function x2βˆ’100xβˆ’10\frac{x^2 - 100}{x - 10} is 2020.

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