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(8-10 i)-(-16+2i)=
Express your answer in the form 
(a+bi).

(810i)(16+2i)= (8-10 i)-(-16+2 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .

Full solution

Q. (810i)(16+2i)= (8-10 i)-(-16+2 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .
  1. Identify numbers to subtract: Identify the numbers to be subtracted.\newlineWe have two complex numbers: (810i)(8-10i) and (16+2i)(-16+2i). We need to subtract the second complex number from the first one.
  2. Change subtraction to addition: Change the subtraction to addition by distributing the negative sign to the second complex number.\newline(810i)(16+2i)(8-10i) - (-16+2i) becomes (810i)+(162i)(8-10i) + (16-2i) when we distribute the negative sign.
  3. Combine real parts: Combine the real parts of the complex numbers.\newlineThe real part of the first complex number is 88, and the real part of the second complex number is 1616. Adding these together gives us 8+168 + 16.
  4. Calculate sum of real parts: Calculate the sum of the real parts. 8+16=248 + 16 = 24.
  5. Combine imaginary parts: Combine the imaginary parts of the complex numbers.\newlineThe imaginary part of the first complex number is 10i-10i, and the imaginary part of the second complex number is 2i-2i. Adding these together gives us 10i2i-10i - 2i.
  6. Calculate sum of imaginary parts: Calculate the sum of the imaginary parts. 10i2i-10i - 2i equals 12i-12i.
  7. Combine results in (a+bi)(a+bi) form: Combine the results of the real and imaginary parts to express the answer in the form (a+bi)(a+bi).\newlineThe real part is 2424 and the imaginary part is 12i-12i, so the final answer is 2412i24 - 12i.

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