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-(5c)^(0)+7^(1)-2^(2)
If 
c!=0, what is the value of the given expression?

(5c)0+7122 -(5 c)^{0}+7^{1}-2^{2} \newlineIf c0 c \neq 0 , what is the value of the given expression?

Full solution

Q. (5c)0+7122 -(5 c)^{0}+7^{1}-2^{2} \newlineIf c0 c \neq 0 , what is the value of the given expression?
  1. Evaluate (5c)0(5c)^{0}: We are given the expression (5c)0+7122-(5c)^{0}+7^{1}-2^{2} and the condition that cc is not equal to zero. We need to evaluate the expression step by step.\newlineFirst, we will evaluate the term (5c)0(5c)^{0}.\newlineAny non-zero number raised to the power of 00 is 11.\newlineTherefore, (5c)0=1(5c)^{0} = 1.
  2. Consider Negative Sign: Now we will consider the negative sign in front of (5c)0(5c)^{0}. The expression becomes (5c)0-(5c)^{0} which is 1-1.
  3. Evaluate 717^{1}: Next, we evaluate 717^{1}. Any number raised to the power of 11 is the number itself. Therefore, 71=77^{1} = 7.
  4. Evaluate 222^{2}: Finally, we evaluate 222^{2}. 22 squared is 2×22 \times 2, which equals 44. Therefore, 22=42^{2} = 4.
  5. Combine Evaluated Parts: Now we will combine all the evaluated parts of the expression. The expression becomes 1+74-1 + 7 - 4.
  6. Perform Addition and Subtraction: We perform the addition and subtraction from left to right.\newlineFirst, we add 1-1 and 77, which gives us 66.\newlineThen we subtract 44 from 66, which gives us 22.\newlineTherefore, the final value of the expression is 22.