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Find the values of x.
(4x^(2)-3x-1)/(4x+1)+(x^(3)+1)/(x^(2)-x+1)=2

Find the values of xx.\newline4x23x14x+1+x3+1x2x+1=2 \frac{4 x^{2}-3 x-1}{4 x+1}+\frac{x^{3}+1}{x^{2}-x+1}=2

Full solution

Q. Find the values of xx.\newline4x23x14x+1+x3+1x2x+1=2 \frac{4 x^{2}-3 x-1}{4 x+1}+\frac{x^{3}+1}{x^{2}-x+1}=2
  1. Identify Terms and Denominator: First, let's identify the individual terms of the equation and understand that we need to find a common denominator to combine the fractions on the left side of the equation.
  2. Find Common Denominator: The common denominator for the two fractions (4x+1)(4x+1) and (x2x+1)(x^2-x+1) would be their product, (4x+1)(x2x+1)(4x+1)(x^2-x+1). We will multiply both the numerator and denominator of each fraction by the necessary terms to achieve this common denominator.
  3. Multiply First Fraction: Multiply the first fraction (4x23x1)/(4x+1)(4x^2-3x-1)/(4x+1) by (x2x+1)/(x2x+1)(x^2-x+1)/(x^2-x+1) to get ((4x23x1)(x2x+1))/((4x+1)(x2x+1))((4x^2-3x-1)(x^2-x+1))/((4x+1)(x^2-x+1)).
  4. Multiply Second Fraction: Multiply the second fraction (x3+1)/(x2x+1)(x^3+1)/(x^2-x+1) by (4x+1)/(4x+1)(4x+1)/(4x+1) to get ((x3+1)(4x+1))/((4x+1)(x2x+1))((x^3+1)(4x+1))/((4x+1)(x^2-x+1)).
  5. Combine Fractions: Now, we will add the two fractions together since they have the same denominator. This gives us: (4x23x1)(x2x+1)+(x3+1)(4x+1)(4x+1)(x2x+1)=2\frac{(4x^2-3x-1)(x^2-x+1) + (x^3+1)(4x+1)}{(4x+1)(x^2-x+1)} = 2
  6. Expand First Numerator: We need to expand the numerators of both fractions before adding them. Let's start with the first numerator (4x23x1)(x2x+1)(4x^2-3x-1)(x^2-x+1). We will use the distributive property (FOIL) to expand this product.
  7. Expand Second Numerator: Expanding (4x23x1)(x2x+1)(4x^2-3x-1)(x^2-x+1) gives us 4x44x3+4x23x3+3x23xx2+x14x^4 - 4x^3 + 4x^2 - 3x^3 + 3x^2 - 3x - x^2 + x - 1.
  8. Add Expanded Numerators: Combining like terms in the expanded expression gives us 4x47x3+6x23x14x^4 - 7x^3 + 6x^2 - 3x - 1.
  9. Combine Like Terms: Now let's expand the second numerator (x3+1)(4x+1)(x^3+1)(4x+1) using the distributive property.
  10. Eliminate Denominator: Expanding (x3+1)(4x+1)(x^3+1)(4x+1) gives us 4x4+x3+4x+14x^4 + x^3 + 4x + 1.
  11. Expand Right Side: Now we add the expanded numerators together: 4x47x3+6x23x14x^4 - 7x^3 + 6x^2 - 3x - 1 + 4x4+x3+4x+14x^4 + x^3 + 4x + 1.
  12. Combine Like Terms Right Side: Combining like terms gives us 8x46x3+6x2+x8x^4 - 6x^3 + 6x^2 + x.
  13. Distribute Right Side: Now we have the combined fraction as (8x46x3+6x2+x)/((4x+1)(x2x+1))=2(8x^4 - 6x^3 + 6x^2 + x)/((4x+1)(x^2-x+1)) = 2.
  14. Set Equation to Zero: To solve for xx, we need to get rid of the denominator. We can do this by multiplying both sides of the equation by the denominator, which gives us 8x46x3+6x2+x=2(4x+1)(x2x+1)8x^4 - 6x^3 + 6x^2 + x = 2(4x+1)(x^2-x+1).
  15. Subtract Right Side: Now we need to expand the right side of the equation: 2(4x+1)(x2x+1)2(4x+1)(x^2-x+1).
  16. Quartic Equation Error: Expanding the right side gives us 2(4x34x2+4x+x2x+1)2(4x^3 - 4x^2 + 4x + x^2 - x + 1).
  17. Quartic Equation Error: Expanding the right side gives us 2(4x34x2+4x+x2x+1)2(4x^3 - 4x^2 + 4x + x^2 - x + 1).Combining like terms on the right side gives us 2(4x33x2+3x+1)2(4x^3 - 3x^2 + 3x + 1).
  18. Quartic Equation Error: Expanding the right side gives us 2(4x34x2+4x+x2x+1)2(4x^3 - 4x^2 + 4x + x^2 - x + 1). Combining like terms on the right side gives us 2(4x33x2+3x+1)2(4x^3 - 3x^2 + 3x + 1). Distributing the 22 across the terms on the right side gives us 8x36x2+6x+28x^3 - 6x^2 + 6x + 2.
  19. Quartic Equation Error: Expanding the right side gives us 2(4x34x2+4x+x2x+1)2(4x^3 - 4x^2 + 4x + x^2 - x + 1). Combining like terms on the right side gives us 2(4x33x2+3x+1)2(4x^3 - 3x^2 + 3x + 1). Distributing the 22 across the terms on the right side gives us 8x36x2+6x+28x^3 - 6x^2 + 6x + 2. Now we have the equation 8x46x3+6x2+x=8x36x2+6x+28x^4 - 6x^3 + 6x^2 + x = 8x^3 - 6x^2 + 6x + 2.
  20. Quartic Equation Error: Expanding the right side gives us 2(4x34x2+4x+x2x+1)2(4x^3 - 4x^2 + 4x + x^2 - x + 1). Combining like terms on the right side gives us 2(4x33x2+3x+1)2(4x^3 - 3x^2 + 3x + 1). Distributing the 22 across the terms on the right side gives us 8x36x2+6x+28x^3 - 6x^2 + 6x + 2. Now we have the equation 8x46x3+6x2+x=8x36x2+6x+28x^4 - 6x^3 + 6x^2 + x = 8x^3 - 6x^2 + 6x + 2. We need to bring all terms to one side to set the equation to zero: 8x46x3+6x2+x(8x36x2+6x+2)=08x^4 - 6x^3 + 6x^2 + x - (8x^3 - 6x^2 + 6x + 2) = 0.
  21. Quartic Equation Error: Expanding the right side gives us 2(4x34x2+4x+x2x+1)2(4x^3 - 4x^2 + 4x + x^2 - x + 1). Combining like terms on the right side gives us 2(4x33x2+3x+1)2(4x^3 - 3x^2 + 3x + 1). Distributing the 22 across the terms on the right side gives us 8x36x2+6x+28x^3 - 6x^2 + 6x + 2. Now we have the equation 8x46x3+6x2+x=8x36x2+6x+28x^4 - 6x^3 + 6x^2 + x = 8x^3 - 6x^2 + 6x + 2. We need to bring all terms to one side to set the equation to zero: 8x46x3+6x2+x(8x36x2+6x+2)=08x^4 - 6x^3 + 6x^2 + x - (8x^3 - 6x^2 + 6x + 2) = 0. Subtracting the terms on the right from the left gives us 8x414x3+12x25x2=08x^4 - 14x^3 + 12x^2 - 5x - 2 = 0.
  22. Quartic Equation Error: Expanding the right side gives us 2(4x34x2+4x+x2x+1)2(4x^3 - 4x^2 + 4x + x^2 - x + 1). Combining like terms on the right side gives us 2(4x33x2+3x+1)2(4x^3 - 3x^2 + 3x + 1). Distributing the 22 across the terms on the right side gives us 8x36x2+6x+28x^3 - 6x^2 + 6x + 2. Now we have the equation 8x46x3+6x2+x=8x36x2+6x+28x^4 - 6x^3 + 6x^2 + x = 8x^3 - 6x^2 + 6x + 2. We need to bring all terms to one side to set the equation to zero: 8x46x3+6x2+x(8x36x2+6x+2)=08x^4 - 6x^3 + 6x^2 + x - (8x^3 - 6x^2 + 6x + 2) = 0. Subtracting the terms on the right from the left gives us 8x414x3+12x25x2=08x^4 - 14x^3 + 12x^2 - 5x - 2 = 0. This is a quartic equation, and solving it algebraically can be very complex. We would typically use numerical methods or graphing to find the roots. However, there is a mistake in the previous steps. The derivative of ln(2x)\ln(2x) is not 1/x1/x as stated in Step 33 of the full solution. The correct derivative should be 1/x1/x multiplied by the derivative of the inner function 2(4x33x2+3x+1)2(4x^3 - 3x^2 + 3x + 1)00, which is 22. Therefore, the correct derivative of ln(2x)\ln(2x) is 2(4x33x2+3x+1)2(4x^3 - 3x^2 + 3x + 1)33. This means there is a math error in the full solution provided.

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