Equations Given: We have the system of equations: 1) -3x + 3y = 4 2) -x + y = 3 Let's solve the second equation for y. y = x + 3Solve for y: Now, substitute y = x + 3 into the first equation. -3x + 3(x + 3) = 4Substitute into first equation: Distribute the 3 into the parentheses. -3x + 3x + 9 = 4Distribute and simplify: Combine like terms. 0x + 9 = 4Combine like terms: Since 0x is 0, we have 9 = 4, which is not true. This indicates that there is no solution for x that will satisfy both equations simultaneously. This means the system of equations is inconsistent.

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$-3$ $x$ + $3$ $y$ = $4$ - $x$ + $y$ = $3$

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Algebra 1

Solve linear equations: mixed review

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-3

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3

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4

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3

Equations Given: We have the system of equations: $\newline$ $1$ ) $-3x + 3y = 4$ $\newline$ $2$ ) $-x + y = 3$ $\newline$ Let's solve the second equation for y. $\newline$ $y = x + 3$
Solve for y: Now, substitute $y = x + 3$ into the first equation. $\newline$ $-3x + 3(x + 3) = 4$
Substitute into first equation: Distribute the $3$ into the parentheses. $\newline$ $-3x + 3x + 9 = 4$
Distribute and simplify: Combine like terms. $\newline$ $0x + 9 = 4$
Combine like terms: Since $0x$ is $0$ , we have $9 = 4$ , which is not true. This indicates that there is no solution for $x$ that will satisfy both equations simultaneously. This means the system of equations is inconsistent.