Substitute y into first equation: First, we will substitute the expression for y from the second equation into the first equation. -3x - 3(-5x - 17) = 3Distribute and simplify: Now, distribute the -3 into the parentheses. -3x + 15x + 51 = 3Combine like terms: Combine like terms on the left side of the equation. 12x + 51 = 3Isolate x term: Subtract 51 from both sides of the equation to isolate the term with x. 12x + 51 - 51 = 3 - 51 12x = -48Solve for x: Divide both sides by 12 to solve for x. 12x / 12 = -48 / 12 x = -4Substitute x into second equation: Now that we have the value of x, we can substitute it back into the second equation to solve for y. y = -5(-4) - 17Calculate y: Perform the multiplication and subtraction to find the value of y. y = 20 - 17 y = 3

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$-3x - 3y = 3$ $\newline$ $y = -5x - 17$

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Math Problems

Algebra 1

Solve linear equations with variables on both sides

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-3x - 3y = 3

\newline

y = -5x - 17

Substitute $y$ into first equation: First, we will substitute the expression for $y$ from the second equation into the first equation. $\newline$ $-3x - 3(-5x - 17) = 3$
Distribute and simplify: Now, distribute the $-3$ into the parentheses. $-3x + 15x + 51 = 3$
Combine like terms: Combine like terms on the left side of the equation. $12x + 51 = 3$
Isolate x term: Subtract $51$ from both sides of the equation to isolate the term with $x$ . $\newline$ $12x + 51 - 51 = 3 - 51$ $\newline$ $12x = -48$
Solve for x: Divide both sides by $12$ to solve for x. $\newline$ $\frac{12x}{12} = \frac{-48}{12}$ $\newline$ $x = -4$
Substitute $x$ into second equation: Now that we have the value of $x$ , we can substitute it back into the second equation to solve for $y$ . $y = -5(-4) - 17$
Calculate $y$ : Perform the multiplication and subtraction to find the value of $y$ . $y = 20 - 17$ $y = 3$