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[3(2j5k2)]2[-3(2j-5k^2)]^2

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Q. [3(2j5k2)]2[-3(2j-5k^2)]^2
  1. Distribute and Calculate: Distribute the 3-3 inside the parentheses to both terms 2j2j and 5k2-5k^2.\newlineCalculation: 3×2j=6j-3 \times 2j = -6j and 3×5k2=15k2-3 \times -5k^2 = 15k^2\newlineSo, the expression inside the parentheses becomes 6j+15k2-6j + 15k^2.
  2. Square Expression: Square the entire expression inside the parentheses.\newlineCalculation: (6j+15k2)2(-6j + 15k^2)^2\newlineThis means we need to multiply the expression by itself: (6j+15k2)×(6j+15k2)(-6j + 15k^2) \times (-6j + 15k^2)
  3. Apply FOIL Method: Apply the distributive property (FOIL method) to multiply the two binomials.\newlineCalculation: (6j)2+2(6j)(15k2)+(15k2)2(-6j)^2 + 2(-6j)(15k^2) + (15k^2)^2
  4. Calculate Terms: Calculate each term separately.\newlineCalculation: (6j)2=36j2(-6j)^2 = 36j^2, 2(6j)(15k2)=180jk22(-6j)(15k^2) = -180jk^2, and (15k2)2=225k4(15k^2)^2 = 225k^4\newlineSo, the expanded form is 36j2180jk2+225k436j^2 - 180jk^2 + 225k^4
  5. Combine for Final Result: Combine the calculated terms to get the final result.\newlineCalculation: 36j2180jk2+225k436j^2 - 180jk^2 + 225k^4

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