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(2x-1)(x-5)(x+2)=0 What is a positive root of the given equation?

(2x−1)(x−5)(x+2)=0 (2 x-1)(x-5)(x+2)=0 \newlineWhat is a positive root of the given equation?

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Q. (2x−1)(x−5)(x+2)=0 (2 x-1)(x-5)(x+2)=0 \newlineWhat is a positive root of the given equation?
  1. Identify roots of equation: Identify the roots of the equation by setting each factor equal to zero.\newline(2x−1)=0(2x-1)=0, (x−5)=0(x-5)=0, and (x+2)=0(x+2)=0
  2. Solve first equation: Solve the first equation (2x−1)=0(2x-1)=0 for xx.2x−1=02x-1=02x=12x=1x=12x=\frac{1}{2}
  3. Solve second equation: Solve the second equation (x−5)=0(x-5)=0 for xx.x−5=0x-5=0x=5x=5
  4. Solve third equation: Solve the third equation (x+2)=0(x+2)=0 for xx.x+2=0x+2=0x=−2x=-2
  5. Identify positive roots: Identify the positive roots from the solutions found.\newlineThe positive roots are x=12x=\frac{1}{2} and x=5x=5.

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