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(24 y-8)+7=29
Given the equation, what is the value of 
3y-1 ?
Choose 1 answer:
(A) 
(5)/(4)
(B) 
(11)/(8)
(C) 
(11)/(4)
(D) 
(29)/(8)

(24y8)+7=29 (24 y-8)+7=29 \newlineGiven the equation, what is the value of 3y1 3 y-1 ?\newlineChoose 11 answer:\newline(A) 54 \frac{5}{4} \newline(B) 118 \frac{11}{8} \newline(C) 114 \frac{11}{4} \newline(D) 298 \frac{29}{8}

Full solution

Q. (24y8)+7=29 (24 y-8)+7=29 \newlineGiven the equation, what is the value of 3y1 3 y-1 ?\newlineChoose 11 answer:\newline(A) 54 \frac{5}{4} \newline(B) 118 \frac{11}{8} \newline(C) 114 \frac{11}{4} \newline(D) 298 \frac{29}{8}
  1. Simplify left side: First, simplify the left side of the equation by combining like terms.\newline(24y8)+7=24y8+7=24y1(24y - 8) + 7 = 24y - 8 + 7 = 24y - 1\newlineNow the equation is 24y1=2924y - 1 = 29.
  2. Add 11 to isolate y: Next, add 11 to both sides of the equation to isolate the term with y.\newline24y1+1=29+124y - 1 + 1 = 29 + 1\newlineThis simplifies to 24y=3024y = 30.
  3. Divide by 2424: Now, divide both sides of the equation by 2424 to solve for yy.24y24=3024\frac{24y}{24} = \frac{30}{24}This simplifies to y=3024y = \frac{30}{24}.
  4. Reduce fraction: Reduce the fraction 3024\frac{30}{24} to its simplest form.\newlineBoth the numerator and the denominator are divisible by 66.\newliney=(30/6)(24/6)y = \frac{(30 / 6)}{(24 / 6)}\newliney=54y = \frac{5}{4}
  5. Find 3y13y - 1: Now that we have the value of yy, we can find the value of 3y13y - 1.\newline3y1=3(54)13y - 1 = 3\left(\frac{5}{4}\right) - 1
  6. Multiply by 33: Multiply 33 by 54\frac{5}{4} to get the first part of the expression.\newline3(54)=1543\left(\frac{5}{4}\right) = \frac{15}{4}
  7. Subtract 11: Now subtract 11 from 154\frac{15}{4}. Since 11 is the same as 44\frac{4}{4}, we can write:\newline15444=(154)4\frac{15}{4} - \frac{4}{4} = \frac{(15 - 4)}{4}
  8. Perform subtraction: Perform the subtraction in the numerator.\newline(154)/4=11/4(15 - 4) / 4 = 11 / 4

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