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Let’s check out your problem:
(
24
y
−
8
)
+
7
=
29
(24 y-8)+7=29
(
24
y
−
8
)
+
7
=
29
\newline
Given the equation, what is the value of
3
y
−
1
3 y-1
3
y
−
1
?
\newline
Choose
1
1
1
answer:
\newline
(A)
5
4
\frac{5}{4}
4
5
\newline
(B)
11
8
\frac{11}{8}
8
11
\newline
(C)
11
4
\frac{11}{4}
4
11
\newline
(D)
29
8
\frac{29}{8}
8
29
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Math Problems
Algebra 1
Solve linear equations: mixed review
Full solution
Q.
(
24
y
−
8
)
+
7
=
29
(24 y-8)+7=29
(
24
y
−
8
)
+
7
=
29
\newline
Given the equation, what is the value of
3
y
−
1
3 y-1
3
y
−
1
?
\newline
Choose
1
1
1
answer:
\newline
(A)
5
4
\frac{5}{4}
4
5
\newline
(B)
11
8
\frac{11}{8}
8
11
\newline
(C)
11
4
\frac{11}{4}
4
11
\newline
(D)
29
8
\frac{29}{8}
8
29
Simplify left side:
First, simplify the left side of the equation by combining like terms.
\newline
(
24
y
−
8
)
+
7
=
24
y
−
8
+
7
=
24
y
−
1
(24y - 8) + 7 = 24y - 8 + 7 = 24y - 1
(
24
y
−
8
)
+
7
=
24
y
−
8
+
7
=
24
y
−
1
\newline
Now the equation is
24
y
−
1
=
29
24y - 1 = 29
24
y
−
1
=
29
.
Add
1
1
1
to isolate y:
Next, add
1
1
1
to both sides of the equation to isolate the term with y.
\newline
24
y
−
1
+
1
=
29
+
1
24y - 1 + 1 = 29 + 1
24
y
−
1
+
1
=
29
+
1
\newline
This simplifies to
24
y
=
30
24y = 30
24
y
=
30
.
Divide by
24
24
24
:
Now, divide both sides of the equation by
24
24
24
to solve for
y
y
y
.
24
y
24
=
30
24
\frac{24y}{24} = \frac{30}{24}
24
24
y
=
24
30
This simplifies to
y
=
30
24
y = \frac{30}{24}
y
=
24
30
.
Reduce fraction:
Reduce the
fraction
30
24
\frac{30}{24}
24
30
to its simplest form.
\newline
Both the numerator and the denominator are divisible by
6
6
6
.
\newline
y
=
(
30
/
6
)
(
24
/
6
)
y = \frac{(30 / 6)}{(24 / 6)}
y
=
(
24/6
)
(
30/6
)
\newline
y
=
5
4
y = \frac{5}{4}
y
=
4
5
Find
3
y
−
1
3y - 1
3
y
−
1
:
Now that we have the value of
y
y
y
, we can find the value of
3
y
−
1
3y - 1
3
y
−
1
.
\newline
3
y
−
1
=
3
(
5
4
)
−
1
3y - 1 = 3\left(\frac{5}{4}\right) - 1
3
y
−
1
=
3
(
4
5
)
−
1
Multiply by
3
3
3
:
Multiply
3
3
3
by
5
4
\frac{5}{4}
4
5
to get the first part of the expression.
\newline
3
(
5
4
)
=
15
4
3\left(\frac{5}{4}\right) = \frac{15}{4}
3
(
4
5
)
=
4
15
Subtract
1
1
1
:
Now subtract
1
1
1
from
15
4
\frac{15}{4}
4
15
. Since
1
1
1
is the same as
4
4
\frac{4}{4}
4
4
, we can write:
\newline
15
4
−
4
4
=
(
15
−
4
)
4
\frac{15}{4} - \frac{4}{4} = \frac{(15 - 4)}{4}
4
15
−
4
4
=
4
(
15
−
4
)
Perform subtraction:
Perform the subtraction in the numerator.
\newline
(
15
−
4
)
/
4
=
11
/
4
(15 - 4) / 4 = 11 / 4
(
15
−
4
)
/4
=
11/4
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4
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(\frac{3}{4})x= 12
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1
1
answer:
\newline
(A) No solutions
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(B) Exactly one solution
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6
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9
x
+
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\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
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(C) Infinitely many solutions
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)
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x
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2
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−
6
(
x
+
7
)
=
−
4
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−
2
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
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\newline
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1
1
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answer:
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(B) Exactly one solution
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17
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\newline
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1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
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How many solutions does the following equation have?
\newline
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=
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=
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Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
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(C) Infinitely many solutions
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