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Prove that  (1)/(csc^(2)theta)+sec^(2)theta+(1)/(sec^(2)theta)=2+(sec^(2)theta)/(csc^(2)theta)

Prove that 1csc2θ+sec2θ+1sec2θ=2+sec2θcsc2θ\frac{1}{\csc^{2}\theta}+\sec^{2}\theta+\frac{1}{\sec^{2}\theta}=2+\frac{\sec^{2}\theta}{\csc^{2}\theta}

Full solution

Q. Prove that 1csc2θ+sec2θ+1sec2θ=2+sec2θcsc2θ\frac{1}{\csc^{2}\theta}+\sec^{2}\theta+\frac{1}{\sec^{2}\theta}=2+\frac{\sec^{2}\theta}{\csc^{2}\theta}
  1. Recall Definitions: First, let's recall the definitions of the secant and cosecant functions in terms of sine and cosine:\newlinesec(θ)=1cos(θ)\sec(\theta) = \frac{1}{\cos(\theta)}\newlinecsc(θ)=1sin(θ)\csc(\theta) = \frac{1}{\sin(\theta)}\newlineWe will use these definitions to rewrite the given expression in terms of sine and cosine.
  2. Rewrite First Term: Now, let's rewrite the first term (1)/(csc2θ)(1)/(\csc^{2}\theta) as sin2θ\sin^{2}\theta:\newline(\(1)/(\csc^{22}\theta) = (11)/((11/\sin(\theta))^22) = \sin^{22}\theta
  3. Rewrite Third Term: Next, we rewrite the third term (1)/(sec2θ)(1)/(\sec^{2}\theta) as cos2θ\cos^{2}\theta:\newline(\(1)/(\sec^{22}\theta) = (11)/((11/\cos(\theta))^22) = \cos^{22}\theta
  4. Rewrite Right Side: Now, let's rewrite the right side of the equation (sec2θ)/(csc2θ)(\sec^{2}\theta)/(\csc^{2}\theta) as (1/cos2θ)/(1/sin2θ)(1/\cos^{2}\theta)/(1/\sin^{2}\theta), which simplifies to sin2θ/cos2θ\sin^{2}\theta/\cos^{2}\theta, which is tan2θ\tan^{2}\theta:(\sec^{\(2\)}\theta)/(\csc^{\(2\)}\theta) = (\(1/\cos^{22}\theta)/(11/\sin^{22}\theta) = \sin^{22}\theta/\cos^{22}\theta = \tan^{22}\theta
  5. Rewrite Entire Equation: We can now rewrite the entire equation using these trigonometric identities: sin2θ+sec2θ+cos2θ=2+tan2θ\sin^{2}\theta + \sec^{2}\theta + \cos^{2}\theta = 2 + \tan^{2}\theta
  6. Apply Pythagorean Identity: We know from the Pythagorean identity that sin2θ+cos2θ=1\sin^{2}\theta + \cos^{2}\theta = 1. Let's apply this identity to simplify the left side of the equation:\newline1+sec2θ=2+tan2θ1 + \sec^{2}\theta = 2 + \tan^{2}\theta
  7. Substitute Identity: Another Pythagorean identity tells us that sec2θ=1+tan2θ\sec^2\theta = 1 + \tan^2\theta. Let's substitute this into the equation:\newline1+(1+tan2θ)=2+tan2θ1 + (1 + \tan^2\theta) = 2 + \tan^2\theta
  8. Simplify Left Side: Now, simplify the left side of the equation by combining like terms: 2+tan2θ=2+tan2θ2 + \tan^2\theta = 2 + \tan^2\theta
  9. Verify Equality: We see that both sides of the equation are equal, which means the original expression is an identity.

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