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Math Problems
Grade 7
Add integers
Subtract
−
2
(
3
p
+
2
)
-2(3p + 2)
−
2
(
3
p
+
2
)
from
2
p
+
6
2p + 6
2
p
+
6
.
\newline
Simplify your expression and provide the final result.
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Evaluate.
\newline
−
12
÷
4
=
-12 \div 4=
−
12
÷
4
=
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Evaluate.
\newline
−
10
÷
(
−
2
)
=
-10 \div(-2)=
−
10
÷
(
−
2
)
=
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Evaluate.
\newline
−
2
÷
2
=
-2 \div 2=
−
2
÷
2
=
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Evaluate.
\newline
2
÷
(
−
2
)
=
2 \div(-2)=
2
÷
(
−
2
)
=
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Evaluate.
\newline
−
8
÷
(
−
4
)
=
-8 \div(-4)=
−
8
÷
(
−
4
)
=
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Evaluate.
\newline
−
18
÷
−
3
=
-18 \div-3=
−
18
÷
−
3
=
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Evaluate.
\newline
−
42
÷
6
=
-42 \div 6=
−
42
÷
6
=
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Evaluate.
\newline
−
24
÷
6
=
-24 \div 6=
−
24
÷
6
=
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Evaluate.
\newline
12
÷
(
−
6
)
=
12 \div(-6)=
12
÷
(
−
6
)
=
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Evaluate.
\newline
6
÷
(
−
1
)
=
6 \div(-1)=
6
÷
(
−
1
)
=
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Evaluate.
\newline
−
45
÷
(
−
9
)
=
-45 \div(-9)=
−
45
÷
(
−
9
)
=
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Evaluate.
\newline
−
35
÷
(
−
7
)
=
-35 \div(-7)=
−
35
÷
(
−
7
)
=
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Evaluate.
\newline
48
÷
(
−
8
)
=
48 \div(-8)=
48
÷
(
−
8
)
=
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Evaluate.
\newline
63
÷
(
−
9
)
=
63 \div(-9)=
63
÷
(
−
9
)
=
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Evaluate.
\newline
−
3
×
4
=
-3 \times 4=
−
3
×
4
=
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Evaluate.
\newline
2
×
(
−
4
)
=
2 \times(-4)=
2
×
(
−
4
)
=
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Evaluate.
\newline
−
1
×
2
=
-1 \times 2=
−
1
×
2
=
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Evaluate.
\newline
0
×
(
−
4
)
=
0 \times(-4)=
0
×
(
−
4
)
=
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Evaluate.
\newline
−
7
×
6
=
-7 \times 6=
−
7
×
6
=
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Evaluate.
\newline
−
1
×
(
−
2
)
=
-1 \times(-2)=
−
1
×
(
−
2
)
=
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Evaluate.
\newline
5
×
(
−
7
)
=
5 \times(-7)=
5
×
(
−
7
)
=
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Evaluate.
\newline
−
4
×
6
=
-4 \times 6=
−
4
×
6
=
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Evaluate.
\newline
−
7
×
(
−
9
)
=
-7 \times(-9)=
−
7
×
(
−
9
)
=
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Evaluate.
\newline
−
6
×
5
=
-6 \times 5=
−
6
×
5
=
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Evaluate.
\newline
−
3
×
(
−
9
)
=
-3 \times(-9)=
−
3
×
(
−
9
)
=
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Evaluate.
\newline
−
6
×
(
−
8
)
=
-6 \times(-8)=
−
6
×
(
−
8
)
=
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Evaluate.
\newline
5
×
(
−
9
)
=
5 \times(-9)=
5
×
(
−
9
)
=
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Evaluate.
\newline
−
4
×
(
−
9
)
=
-4 \times(-9)=
−
4
×
(
−
9
)
=
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Evaluate.
\newline
−
5
×
(
−
2
)
=
-5 \times(-2)=
−
5
×
(
−
2
)
=
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Evaluate.
\newline
9
×
(
−
8
)
=
9 \times(-8)=
9
×
(
−
8
)
=
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Evaluate.
\newline
−
7
×
7
=
-7 \times 7=
−
7
×
7
=
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Evaluate.
\newline
27
÷
(
−
9
)
=
27 \div(-9)=
27
÷
(
−
9
)
=
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Evaluate.
\newline
0
÷
(
−
4
)
=
0 \div(-4)=
0
÷
(
−
4
)
=
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Evaluate.
\newline
−
49
÷
7
=
-49 \div 7=
−
49
÷
7
=
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Evaluate.
\newline
−
72
÷
(
−
8
)
=
-72 \div(-8)=
−
72
÷
(
−
8
)
=
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Solve for
x
x
x
.
\newline
−
5
<
7
+
2
x
-5<7+2x
−
5
<
7
+
2
x
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1
−
3
5
=
1-\frac{3}{5}=
1
−
5
3
=
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(
−
16
)
÷
(
−
4
)
=
(-16) \div(-4)=
(
−
16
)
÷
(
−
4
)
=
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Q
5
−
2
5-2
5
−
2
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Q
2
−
3
2-3
2
−
3
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Compute:
\newline
−
12
+
(
−
11
)
-12+(-11)
−
12
+
(
−
11
)
\newline
Answer:
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Compute:
\newline
7
+
(
−
3
)
7+(-3)
7
+
(
−
3
)
\newline
Answer:
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Compute:
\newline
(
−
8
)
+
(
−
4
)
(-8)+(-4)
(
−
8
)
+
(
−
4
)
\newline
Answer:
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Compute:
\newline
11
+
(
−
8
)
11+(-8)
11
+
(
−
8
)
\newline
Answer:
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Compute:
\newline
−
4
−
(
−
7
)
-4-(-7)
−
4
−
(
−
7
)
\newline
Answer:
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−
(
7
−
4
x
)
=
9
-(7-4 x)=9
−
(
7
−
4
x
)
=
9
\newline
x
=
x=
x
=
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1
+
1
=
1+1=
1
+
1
=
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Evaluate:
\newline
(
−
3
2
)
4
=
(-\frac{3}{2})^{4}=
(
−
2
3
)
4
=
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Find the
1
1
1
oth term of the arithmetic sequence
−
5
x
+
5
,
x
+
1
,
7
x
−
3
,
…
-5 x+5, x+1,7 x-3, \ldots
−
5
x
+
5
,
x
+
1
,
7
x
−
3
,
…
\newline
Answer:
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1
2
3
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