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Find the 1oth term of the arithmetic sequence 
-5x+5,x+1,7x-3,dots
Answer:

Find the 11oth term of the arithmetic sequence 5x+5,x+1,7x3, -5 x+5, x+1,7 x-3, \ldots \newlineAnswer:

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Q. Find the 11oth term of the arithmetic sequence 5x+5,x+1,7x3, -5 x+5, x+1,7 x-3, \ldots \newlineAnswer:
  1. Find Common Difference: To find the 10th10^{\text{th}} term of an arithmetic sequence, we first need to determine the common difference (dd) between consecutive terms.\newlineLet's find the difference between the second and the first term.\newlineSubtract the first term from the second term: (x+1)(5x+5)(x+1) - (-5x+5).\newlineSimplify the expression: x+1+5x5x + 1 + 5x - 5.\newlineCombine like terms: 6x46x - 4.
  2. Calculate Differences: Now, let's find the difference between the third and the second term.\newlineSubtract the second term from the third term: (7x3)(x+1)(7x-3) - (x+1).\newlineSimplify the expression: 7x3x17x - 3 - x - 1.\newlineCombine like terms: 6x46x - 4.
  3. Confirm Arithmetic Sequence: We have found that the common difference dd is 6x46x - 4 for both the first and second intervals. This confirms that the sequence is arithmetic and that the common difference is consistent.
  4. Use Formula for 1010th Term: To find the 1010th term a10a_{10}, we use the formula for the nth term of an arithmetic sequence: an=a1+(n1)da_n = a_1 + (n - 1)d. Here, a1a_1 is the first term (5x+5)(-5x+5), nn is the term number 1010, and dd is the common difference (6x4)(6x - 4). Let's plug in the values: a10=(5x+5)+(101)(6x4)a_{10} = (-5x+5) + (10 - 1)(6x - 4).
  5. Simplify 1010th Term Calculation: Simplify the expression for the 1010th term.\newlineFirst, calculate (101):9(10 - 1): 9.\newlineThen multiply 99 by the common difference (6x4)(6x - 4): 9(6x4)9(6x - 4).\newlineThis gives us: 54x3654x - 36.\newlineNow add this to the first term (5x+5)(-5x+5): (5x+5)+(54x36)(-5x+5) + (54x - 36).
  6. Combine Terms for 1010th Term: Combine like terms to find the 10th10^{th} term.\newlineAdd the xx terms: 5x+54x=49x-5x + 54x = 49x.\newlineAdd the constant terms: 536=315 - 36 = -31.\newlineSo, the 10th10^{th} term is: 49x3149x - 31.

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