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Math Problems
Grade 6
Multiply two decimals: where does the decimal point go?
Solve the equation.
\newline
f
−
8
9
=
5
9
f
=
\begin{array}{l} f-\frac{8}{9}=\frac{5}{9} \\ f= \end{array}
f
−
9
8
=
9
5
f
=
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Solve the equation.
\newline
2.2
=
z
−
1.1
z
=
□
\begin{array}{l} 2.2=z-1.1 \\ z=\square \end{array}
2.2
=
z
−
1.1
z
=
□
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Solve the equation.
\newline
18
+
k
=
30
k
=
□
\begin{array}{r} 18+k=30 \\ k=\square \end{array}
18
+
k
=
30
k
=
□
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Solve the equation.
\newline
k
+
22
=
29
k
=
□
\begin{array}{r} k+22=29 \\ k=\square \end{array}
k
+
22
=
29
k
=
□
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Solve the equation.
\newline
k
−
8
=
11.8
k
=
□
\begin{array}{l} k-8=11.8 \\ k=\square \end{array}
k
−
8
=
11.8
k
=
□
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Solve the equation.
\newline
6.2
=
2.2
+
x
x
=
□
\begin{array}{l} 6.2=2.2+x \\ x=\square \end{array}
6.2
=
2.2
+
x
x
=
□
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Solve the equation.
\newline
0.15
=
y
−
0.45
y
=
□
\begin{array}{l} 0.15=y-0.45 \\ y=\square \end{array}
0.15
=
y
−
0.45
y
=
□
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5
(
x
−
y
)
+
4
=
7
5(x-y)+4=7
5
(
x
−
y
)
+
4
=
7
\newline
Given the equation, what is the value of
x
−
y
x-y
x
−
y
?
\newline
Choose
1
1
1
answer:
\newline
(A)
−
11
5
-\frac{11}{5}
−
5
11
\newline
(B)
−
3
5
-\frac{3}{5}
−
5
3
\newline
(C)
3
5
\frac{3}{5}
5
3
\newline
(D)
11
5
\frac{11}{5}
5
11
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3
(
2
n
−
2
)
−
1
=
9
4
3(2 n-2)-1=\frac{9}{4}
3
(
2
n
−
2
)
−
1
=
4
9
\newline
Given the equation, what is the value of
2
n
−
2
2 n-2
2
n
−
2
?
\newline
Choose
1
1
1
answer:
\newline
(A)
5
12
\frac{5}{12}
12
5
\newline
(B)
13
12
\frac{13}{12}
12
13
\newline
(C)
7
4
\frac{7}{4}
4
7
\newline
(D)
13
4
\frac{13}{4}
4
13
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−
3
a
+
5
b
=
11
6
a
+
2
b
=
26
\begin{aligned} -3 a+5 b & =11 \\ 6 a+2 b & =26 \end{aligned}
−
3
a
+
5
b
6
a
+
2
b
=
11
=
26
\newline
Consider the given system of equations. If
(
a
,
b
)
(a, b)
(
a
,
b
)
is the solution to the system, then what is the value of
a
b
\frac{a}{b}
b
a
?
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y
=
0.25
x
+
12
y
=
K
(
x
+
3
)
\begin{array}{l} y=0.25 x+12 \\ y=K(x+3) \end{array}
y
=
0.25
x
+
12
y
=
K
(
x
+
3
)
\newline
In the system of equations,
K
K
K
is a constant. For which value of
K
K
K
does the system have no solution?
\newline
Choose
1
1
1
answer:
\newline
(A)
0
0
0
\newline
(B)
0
0
0
.
25
25
25
\newline
(C)
0
0
0
.
75
75
75
\newline
(D)
12
12
12
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−
11
y
=
6
(
z
+
1
)
−
13
y
4
y
−
24
=
c
(
z
−
1
)
\begin{aligned} -11 y & =6(z+1)-13 y \\ 4 y-24 & =c(z-1) \end{aligned}
−
11
y
4
y
−
24
=
6
(
z
+
1
)
−
13
y
=
c
(
z
−
1
)
\newline
For what value of
c
c
c
does the system of linear equations in the variables
y
y
y
and
z
z
z
have infinitely many solutions?
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24
−
6
y
=
2
x
24-6 y=2 x
24
−
6
y
=
2
x
\newline
6
(
y
−
2
)
=
3
+
x
6(y-2)=3+x
6
(
y
−
2
)
=
3
+
x
\newline
Consider the system of equations. If
(
x
,
y
)
(x, y)
(
x
,
y
)
is the solution to the system, then what is the value of
y
+
x
y+x
y
+
x
?
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What is
y
=
−
1
3
x
−
9
y=-\frac{1}{3} x-9
y
=
−
3
1
x
−
9
written in standard form?
\newline
Choose
1
1
1
answer:
\newline
(A)
x
+
3
y
=
−
27
x+3 y=-27
x
+
3
y
=
−
27
\newline
B
y
=
−
1
3
(
x
+
27
)
y=-\frac{1}{3}(x+27)
y
=
−
3
1
(
x
+
27
)
\newline
(C)
3
y
=
−
x
−
27
3 y=-x-27
3
y
=
−
x
−
27
\newline
(D)
1
3
x
+
y
+
9
=
0
\frac{1}{3} x+y+9=0
3
1
x
+
y
+
9
=
0
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15
x
−
3
=
9
x
+
1
15x - 3 = 9x + 1
15
x
−
3
=
9
x
+
1
\newline
Which of the following is the solution to the equation shown?
\newline
Choose
1
1
1
answer:
\newline
(A)
x
=
1
6
x=\frac{1}{6}
x
=
6
1
\newline
(B)
x
=
−
2
3
x=-\frac{2}{3}
x
=
−
3
2
\newline
(C)
x
=
2
3
x=\frac{2}{3}
x
=
3
2
\newline
(D)
x
=
1
x=1
x
=
1
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Evaluate.
\newline
(
1
4
)
2
=
(\frac{1}{4})^{2}=
(
4
1
)
2
=
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Multiply.
0.5
×
5
=
?
0.5 \times 5 = ?
0.5
×
5
=
?
\newline
Choices:
\newline
(A)
0.025
0.025
0.025
\newline
(B)
0.25
0.25
0.25
\newline
(C)
2.5
2.5
2.5
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