{:[24-6y=2x],[6(y-2)=3+x]:} Consider the system of equations. If (x,y) is the solution to the system, then what is the value of y+x ?

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{:[24-6y=2x],[6(y-2)=3+x]:} Consider the system of equations. If  (x,y) is the solution to the system, then what is the value of  y+x ?

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Solve for x: Solve the first equation for x. We have 24 - 6y = 2x. To solve for x, we divide both sides by 2. x = (24 - 6y) / 2 x = 12 - 3ySubstitute x into second equation: Substitute the expression for x into the second equation. The second equation is 6(y - 2) = 3 + x. We substitute x with 12 - 3y. 6(y - 2) = 3 + (12 - 3y)Simplify and solve for y: Simplify and solve for y. Expanding the left side, we get: 6y - 12 = 3 + 12 - 3y Combining like terms, we get: 6y + 3y = 3 + 12 + 12 9y = 27 Dividing both sides by 9, we get: y = 27 / 9 y = 3Substitute y into x expression: Substitute the value of y into the expression for x. We have x = 12 - 3y. Now that we know y = 3, we substitute it in. x = 12 - 3(3) x = 12 - 9 x = 3Find y + x: Add the values of x and y to find y + x. y + x = 3 + 3 y + x = 6

$24-6 y=2 x$ $\newline$ $6(y-2)=3+x$ $\newline$ Consider the system of equations. If $(x, y)$ is the solution to the system, then what is the value of $y+x$ ?

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24−6y=2x 24-6 y=2 x 24−6y=2x\newline6(y−2)=3+x 6(y-2)=3+x 6(y−2)=3+x\newlineConsider the system of equations. If (x,y) (x, y) (x,y) is the solution to the system, then what is the value of y+x y+x y+x ?

$24-6 y=2 x$ $\newline$ $6(y-2)=3+x$ $\newline$ Consider the system of equations. If $(x, y)$ is the solution to the system, then what is the value of $y+x$ ?