What is y=-(1)/(3)x-9 written in standard form? Choose 1 answer: (A) x+3y=-27 (B) y=-(1)/(3)(x+27) (c) 3y=-x-27 (D) (1)/(3)x+y+9=0

Step 1: Multiply by 3: To write the equation y = -(1)/(3)x - 9 in standard form, we need to get the x and y terms on one side of the equation and the constant term on the other side. The standard form of a linear equation is Ax + By = C, where A, B, and C are integers, and A should be non-negative.Step 2: Move x term: First, we multiply every term by 3 to eliminate the fraction. This gives us 3y = -x - 27.Step 3: Check standard form: Next, we move the x term to the left side of the equation by adding x to both sides. This results in x + 3y = -27.Now, we check if the equation x + 3y = -27 is in standard form. The coefficients are integers, and the x coefficient is positive, so the equation is in standard form.

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What is
y=-(1)/(3)x-9 written in standard form?
Choose 1 answer:
(A)
x+3y=-27
(B)
y=-(1)/(3)(x+27)
(c)
3y=-x-27
(D)
(1)/(3)x+y+9=0

What is $y=-\frac{1}{3} x-9$ written in standard form? $\newline$ Choose $1$ answer: $\newline$ (A) $x+3 y=-27$ $\newline$ B $y=-\frac{1}{3}(x+27)$ $\newline$ (C) $3 y=-x-27$ $\newline$ (D) $\frac{1}{3} x+y+9=0$

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Grade 6

Multiply two decimals: where does the decimal point go?

Full solution

Q. What is

y=-\frac{1}{3} x-9

written in standard form?

\newline

Choose

1

answer:

\newline

(A)

x+3 y=-27

\newline

y=-\frac{1}{3}(x+27)

\newline

(C)

3 y=-x-27

\newline

(D)

\frac{1}{3} x+y+9=0

Step $1$ : Multiply by $3$ : To write the equation $y = -\frac{1}{3}x - 9$ in standard form, we need to get the $x$ and $y$ terms on one side of the equation and the constant term on the other side. The standard form of a linear equation is $Ax + By = C$ , where $A$ , $B$ , and $C$ are integers, and $A$ should be non-negative.
Step $2$ : Move $x$ term: First, we multiply every term by $3$ to eliminate the fraction. This gives us $3y = -x - 27$ .
Step $3$ : Check standard form: Next, we move the $x$ term to the left side of the equation by adding $x$ to both sides. This results in $x + 3y = -27$ .
Step $3$ : Check standard form: Next, we move the $x$ term to the left side of the equation by adding $x$ to both sides. This results in $x + 3y = -27$ .Now, we check if the equation $x + 3y = -27$ is in standard form. The coefficients are integers, and the $x$ coefficient is positive, so the equation is in standard form.