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Resources

Solve two-step linear inequalities

GIVEN: \Varangle 1 is complementary to \Varangle 3 \Varangle 2 is complementary to

\$ 4

PROVE: \quad 1 \cong \Varangle 2

-3

8

23

-4

26

6

Combine like terms to create an equivalent expression. [

-5

8

4

2

-3

1

1

4

\newline

-4

4

1

1

\newline

-4

4

1

3

\newline

-4

4

1

2

\newline

-4

4

1

4

b

2 < b - 9

h

\newline

5 + -4h < 9

s

\newline

9 + 3s \leq 3

u

\newline

10 + 3u \leq 1

Which statement describes the expression

9(s+25)

\newline

25

9

s

\newline

9

times the quantity

s

25

\newline

9

times the quantity

s

25

\newline

25

9

s

x

2x > 8

m

\newline

\begin{array}{l} 12.6+4 m=9.6+8 m \\ m= \end{array}

\frac{5x}{2}-\frac{3x}{2x}+4

3x<5x+1<16

2 \sin x + \frac{3}{\cos x}

2 f-1 \geq 3

Which expression is equivalent to

2.5 n-9.9+8.8 n+2.8 ?

\newline

-6.3 n-7.1

\newline

11.3 n-7.1

\newline

-6.3 n-12.7

\newline

-7.4 n+11.6

y

\newline

-1y - 5 < -4

k

\newline

1 - 3k \geq 10

g

\newline

8 + -1g > 4

y

\newline

8 + 2y > 2

k

\newline

-1k + 1 < -1

v

\newline

-1v + 8 \geq 6

p

\newline

5p + 7 \leq 2

w

\newline

2w + 10 \geq 8

g

\newline

2 - 7g < 9

h

\newline

1 - 8h > 9

q

\newline

1 - 4q \geq 9

w

\newline

-2w + 1 > -7

s

\newline

8 + 2s \geq 2

b

\newline

-7 + -1b \leq -10

w

\newline

5w - 8 > 2

z

\newline

1 - -2z \leq 7

y

\newline

9 - 4y > 1

a

\newline

2 - 8a \geq 10

t

\newline

-2t - 1 \leq -9

h

\newline

5 - 5h \geq 10

a

\newline

1 - -1a \leq 6

y

\newline

3 + -7y < 10

b

\newline

-3 - -1b \leq -5

k

\newline

-1k + 5 \leq 2

b

\newline

6 - -1b > -1

z

\newline

-4 + 2z \geq 2

k

\newline

-10 + -9k \leq -1

k

\newline

3k + 8 \geq 5

y

\newline

1 - 3y \leq 10

k

\newline

-1 + -1k < -4

q

1 - 2q > 9

g

-9 - (-2g) \leq 1

q

10 + 9q \leq 1

k

-8k - 7 > 1

d

2 - 4d > 10