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Math Problems
Algebra 1
Evaluate a function: plug in an expression
Apply the distributive property to create an equivalent expression
(
−
7
c
+
8
d
)
0.6
(-7c+8d)0.6
(
−
7
c
+
8
d
)
0.6
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Which sign makes the statement true?
\newline
3
5
?
6
10
\frac{3}{5} ? \frac{6}{10}
5
3
?
10
6
\newline
Choices:
\newline
(A)
=
=
=
\newline
(B)
≠
\neq
=
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Which sign makes the statement true?
\newline
50
%
50\%
50%
?
\text{?}
?
1
2
\frac{1}{2}
2
1
\newline
Choices:
\newline
(A)
>
>
>
\newline
(B)
<
<
<
\newline
(C)
=
=
=
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Use the following function rule to find
g
(
4
d
)
g(4d)
g
(
4
d
)
. Simplify your answer.
\newline
g
(
s
)
=
s
−
4
g(s) = s - 4
g
(
s
)
=
s
−
4
\newline
g
(
4
d
)
=
g(4d) =
g
(
4
d
)
=
______
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Use the following function rule to find
f
(
2
r
)
f(2r)
f
(
2
r
)
. Simplify your answer.
\newline
f
(
k
)
=
−
8
k
f(k) = -8k
f
(
k
)
=
−
8
k
\newline
f
(
2
r
)
=
f(2r) =
f
(
2
r
)
=
______
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Use the following function rule to find
h
(
4
t
)
h(4t)
h
(
4
t
)
. Simplify your answer.
\newline
h
(
k
)
=
−
8
k
h(k) = -8k
h
(
k
)
=
−
8
k
\newline
h
(
4
t
)
=
h(4t) =
h
(
4
t
)
=
_
_
\_\_
__
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Use the following function rule to find
f
(
−
8
r
)
f(-8r)
f
(
−
8
r
)
. Simplify your answer.
\newline
f
(
t
)
=
10
t
−
6
f(t) = 10t - 6
f
(
t
)
=
10
t
−
6
\newline
f
(
−
8
r
)
=
f(-8r) =
f
(
−
8
r
)
=
______
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Given
h
(
x
)
=
4
x
+
3
h(x)=4 x+3
h
(
x
)
=
4
x
+
3
, solve for
x
x
x
when
h
(
x
)
=
−
5
h(x)=-5
h
(
x
)
=
−
5
.
\newline
Answer:
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Given
h
(
x
)
=
−
x
−
4
h(x)=-x-4
h
(
x
)
=
−
x
−
4
, find
h
(
−
4
)
h(-4)
h
(
−
4
)
.
\newline
Answer:
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Determine the value of
y
y
y
, if
x
x
x
is
−
6
-6
−
6
.
\newline
y
=
16
x
+
10
y=\frac{16}{x+10}
y
=
x
+
10
16
\newline
Answer:
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Solve for
c
c
c
. Express your answer as a proper or improper fraction in simplest terms.
\newline
−
1
6
=
−
1
2
−
1
6
c
-\frac{1}{6}=-\frac{1}{2}-\frac{1}{6} c
−
6
1
=
−
2
1
−
6
1
c
\newline
Answer:
c
=
c=
c
=
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Solve for
x
\mathrm{x}
x
in simplest form.
\newline
2
=
1
2
(
3
x
+
6
)
2=\frac{1}{2}(3 x+6)
2
=
2
1
(
3
x
+
6
)
\newline
Answer:
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Solve for
w
w
w
and simplify your answer.
\newline
5
2
w
=
−
6
\frac{5}{2} w=-6
2
5
w
=
−
6
\newline
Answer:
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For the following equation, evaluate
d
y
d
x
\frac{d y}{d x}
d
x
d
y
when
x
=
−
1
x=-1
x
=
−
1
.
\newline
y
=
4
x
5
+
3
y=4 x^{5}+3
y
=
4
x
5
+
3
\newline
Answer:
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For the following equation, evaluate
d
y
d
x
\frac{d y}{d x}
d
x
d
y
when
x
=
−
1
x=-1
x
=
−
1
.
\newline
y
=
2
x
5
+
2
x
3
y=2 x^{5}+2 x^{3}
y
=
2
x
5
+
2
x
3
\newline
Answer:
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Use the following function rule to find
g
(
b
+
2
)
g(b + 2)
g
(
b
+
2
)
.
\newline
Simplify your answer.
\newline
g
(
a
)
=
4
a
+
8
g(a) = 4a + 8
g
(
a
)
=
4
a
+
8
g
(
b
+
2
)
=
g(b + 2) =
g
(
b
+
2
)
=
______
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