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You want to know how long it will take for a retirement savings of $50,000\$50,000 to grow to $100,000\$100,000 if it is invested at an annual interest rate of 7%7\%, compounded annually. Use the formula A=P(1+rn)ntA = P\left(1 + \frac{r}{n}\right)^{nt}, where AA is the balance (final amount), PP is the principal (starting amount), rr is the interest rate expressed as a decimal, nn is the number of times per year that the interest is compounded, and tt is the time in years. Round your answer to the nearest hundredth.

Full solution

Q. You want to know how long it will take for a retirement savings of $50,000\$50,000 to grow to $100,000\$100,000 if it is invested at an annual interest rate of 7%7\%, compounded annually. Use the formula A=P(1+rn)ntA = P\left(1 + \frac{r}{n}\right)^{nt}, where AA is the balance (final amount), PP is the principal (starting amount), rr is the interest rate expressed as a decimal, nn is the number of times per year that the interest is compounded, and tt is the time in years. Round your answer to the nearest hundredth.
  1. Identify Values: Identify the values of PP, rr, nn, and AA. P=50000P = 50000 r=0.07r = 0.07 n=1n = 1 A=100000A = 100000
  2. Substitute in Formula: Substitute P=50000P = 50000, r=0.07r = 0.07, n=1n = 1, and A=100000A = 100000 in the formula. 100000=50000(1+0.071)1t100000 = 50000(1 + \frac{0.07}{1})^{1 \cdot t}
  3. Simplify Equation: Simplify the equation.100000=50000(1.07)t100000 = 50000(1.07)^tDivide both sides by 50000.50000. 2=(1.07)t2 = (1.07)^t
  4. Take Natural Logarithm: Take the natural logarithm (\ln) of both sides to solve for t t . ln(2)=ln((1.07)t) \ln(2) = \ln((1.07)^t) ln(2)=tln(1.07) \ln(2) = t \cdot \ln(1.07)
  5. Solve for tt: Solve for tt.\newlinet=ln(2)ln(1.07)t = \frac{\ln(2)}{\ln(1.07)}\newlinet0.6931470.067658t \approx \frac{0.693147}{0.067658}\newlinet10.24t \approx 10.24

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