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Steven opened a savings account and deposited $100.00\$100.00 as principal. The account earns 9%9\% interest, compounded annually. What is the balance after 55 years?\newlineUse the formula A=P(1+rn)ntA = P(1 + \frac{r}{n})^{nt}, where AA is the balance (final amount), PP is the principal (starting amount), rr is the interest rate expressed as a decimal, nn is the number of times per year that the interest is compounded, and tt is the time in years.\newlineRound your answer to the nearest cent.

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Q. Steven opened a savings account and deposited $100.00\$100.00 as principal. The account earns 9%9\% interest, compounded annually. What is the balance after 55 years?\newlineUse the formula A=P(1+rn)ntA = P(1 + \frac{r}{n})^{nt}, where AA is the balance (final amount), PP is the principal (starting amount), rr is the interest rate expressed as a decimal, nn is the number of times per year that the interest is compounded, and tt is the time in years.\newlineRound your answer to the nearest cent.
  1. Identify Variables: Identify the values for the variables in the compound interest formula A=P(1+rn)ntA = P(1 + \frac{r}{n})^{nt}. Here, P=$100P = \$100 (the principal), r=9%r = 9\% or 0.090.09 (the interest rate as a decimal), n=1n = 1 (since the interest is compounded annually), and t=5t = 5 years (the time period).
  2. Substitute Values: Substitute the values into the compound interest formula. A=100(1+(0.09)/(1))(1×5)A = 100(1 + (0.09)/(1))^{(1\times5)}
  3. Simplify Expression: Simplify the expression inside the parentheses and then calculate the exponent. \newlineA=100(1+0.09)5A = 100(1 + 0.09)^5\newlineA=100(1.09)5A = 100(1.09)^5
  4. Calculate Exponent: Calculate the value of (1.09)5(1.09)^5.(1.09)51.53862(1.09)^5 \approx 1.53862 (rounded to five decimal places for intermediate calculation)
  5. Find Final Balance: Multiply the principal by the result from Step 44 to find the final balance.\newlineA=100×1.53862A = 100 \times 1.53862\newlineA153.862A \approx 153.862
  6. Round Final Balance: Round the final balance to the nearest cent. A$(153.86)A \approx \$(153.86)

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