You roll a 6-sided die two times.What is the probability of rolling a number less than 6 and then rolling a number greater than 5?Simplify your answer and write it as a fraction or whole number._____
Q. You roll a 6-sided die two times.What is the probability of rolling a number less than 6 and then rolling a number greater than 5?Simplify your answer and write it as a fraction or whole number._____
Probability of Rolling < 6: The possible outcomes of rolling a die are {1,2,3,4,5,6}. The probability of rolling a number less than 6 is P(\text{Rolling a number} < 6) = \frac{\text{Favorable outcomes}}{\text{Total outcomes}}. Favorable outcomes for rolling a number less than 6 are {1,2,3,4,5}, which gives us 5 favorable outcomes. Total outcomes are 6 because there are 6 sides on the die. So, P(\text{Rolling a number} < 6) = \frac{5}{6}.
Probability of Rolling > 5: Next, we need to find the probability of rolling a number greater than 5. The only number greater than 5 on a 6-sided die is 6.So, the probability of rolling a number greater than 5 is P(\text{Rolling a number} > 5) = \frac{\text{Favorable outcomes}}{\text{Total outcomes}}.Favorable outcomes for rolling a number greater than 5 are \{6\}, which gives us 1 favorable outcome.Total outcomes remain 6.So, P(\text{Rolling a number} > 5) = \frac{1}{6}.
Combined Probability Calculation: Now, we need to find the combined probability of both events happening in sequence. The probability of rolling a number less than 6 and then rolling a number greater than 5 is the product of the individual probabilities.So, P(\text{Rolling a number} < 6 \text{ and then Rolling a number} > 5) = P(\text{Rolling a number} < 6) \times P(\text{Rolling a number} > 5).P(\text{Rolling a number} < 6 \text{ and then Rolling a number} > 5) = \frac{5}{6} \times \frac{1}{6}.
Combined Probability Calculation: Now, we need to find the combined probability of both events happening in sequence. The probability of rolling a number less than 6 and then rolling a number greater than 5 is the product of the individual probabilities.So, P(\text{Rolling a number} < 6 \text{ and then Rolling a number} > 5) = P(\text{Rolling a number} < 6) \times P(\text{Rolling a number} > 5).P(\text{Rolling a number} < 6 \text{ and then Rolling a number} > 5) = (\frac{5}{6}) \times (\frac{1}{6}).Performing the multiplication, we get:P(\text{Rolling a number} < 6 \text{ and then Rolling a number} > 5) = (\frac{5}{6}) \times (\frac{1}{6}) = \frac{5}{36}.This is the simplified fraction that represents the probability of the two events happening in sequence.
More problems from Probability of independent and dependent events