Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

In an experiment, the probability that event A A occurs is 27 \frac{2}{7} , the probability that event B B occurs is 79 \frac{7}{9} , and the probability that events A A and B B both occur is 19 \frac{1}{9} .\newlineAre A A and B B independent events?\newlineChoices:\newline(A) yes\text{yes}\newline(B) no\text{no}

Full solution

Q. In an experiment, the probability that event A A occurs is 27 \frac{2}{7} , the probability that event B B occurs is 79 \frac{7}{9} , and the probability that events A A and B B both occur is 19 \frac{1}{9} .\newlineAre A A and B B independent events?\newlineChoices:\newline(A) yes\text{yes}\newline(B) no\text{no}
  1. Define Independent Events: Define the concept of independent events. Two events, AA and BB, are independent if the occurrence of one does not affect the probability of the occurrence of the other. Mathematically, this means that if AA and BB are independent, then the probability of AA and BB occurring together (P(A and B)P(A \text{ and } B)) is equal to the product of their individual probabilities (P(A)×P(B)P(A) \times P(B)).
  2. Calculate Individual Probabilities: Calculate the product of the individual probabilities of events AA and BB.P(A)×P(B)=(27)×(79)P(A) \times P(B) = \left(\frac{2}{7}\right) \times \left(\frac{7}{9}\right)To calculate this product, we multiply the numerators together and the denominators together.(2×7)/(7×9)=1463\left(2 \times 7\right) / \left(7 \times 9\right) = \frac{14}{63}We can simplify this fraction by dividing both the numerator and the denominator by 77.1463=29\frac{14}{63} = \frac{2}{9}
  3. Compare Probabilities: Compare the product of the individual probabilities to the probability of both events occurring together.\newlineWe have calculated that P(A)×P(B)=29P(A) \times P(B) = \frac{2}{9}. Now we need to compare this to P(A and B)P(A \text{ and } B), which is given as 19\frac{1}{9}.\newlineIf P(A)×P(B)=P(A and B)P(A) \times P(B) = P(A \text{ and } B), then events A and B are independent. If not, they are dependent.\newlineP(A)×P(B)=29P(A) \times P(B) = \frac{2}{9}\newlineP(A and B)=19P(A \text{ and } B) = \frac{1}{9}\newlineSince 29\frac{2}{9} is not equal to 19\frac{1}{9}, the product of the individual probabilities does not equal the probability of both events occurring together.
  4. Conclude Independence: Conclude whether events AA and BB are independent or dependent. Since P(A)×P(B)P(A and B)P(A) \times P(B) \neq P(A \text{ and } B), events AA and BB are not independent. Therefore, they are dependent events.

More problems from Identify independent events