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You pick a card at random. Without putting the first card back, you pick a second card at random. $\newline$ $1234$ $\newline$ What is the probability of picking a $1$ and then picking a $3$ ? $\newline$ Write your answer as a fraction or whole number. $\newline$ $\_\_\_$

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Probability of independent and dependent events

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Q. You pick a card at random. Without putting the first card back, you pick a second card at random.

\newline

1234

\newline

What is the probability of picking a

1

and then picking a

3

?

\newline

Write your answer as a fraction or whole number.

\newline

\_\_\_

Total Number of Cards: Step $1$ : Determine the total number of cards. There are $4$ cards numbered from $1$ to $4$ .
Probability of Picking $1$ : Step $2$ : Calculate the probability of picking a $1$ first. Since there is one ' $1$ ' in four cards, the probability is $\frac{1}{4}$ .
Probability of Picking $3$ : Step $3$ : Calculate the probability of picking a $3$ next, without replacing the first card. Now there are $3$ cards left, and one of them is a ' $3$ '. So, the probability is $\frac{1}{3}$ .
Overall Probability Calculation: Step $4$ : Multiply the probabilities from Step $2$ and Step $3$ to find the overall probability of this sequence ( $1$ then $3$ ). $\frac{1}{4} \times \frac{1}{3} = \frac{1}{12}.$

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Question

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Question

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\newline

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\newline

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\newline

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\newline

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\newline

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\newline

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\newline

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