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You pick a card at random. Without putting the first card back, you pick a second card at random. $\newline$ $1234$ $\newline$ What is the probability of picking a $3$ and then picking a $3$ ? $\newline$ Write your answer as a percentage. $\newline$ $\_\_\_\_\%$

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Probability of independent and dependent events

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Q. You pick a card at random. Without putting the first card back, you pick a second card at random.

\newline

1234

\newline

What is the probability of picking a

3

and then picking a

3

?

\newline

Write your answer as a percentage.

\newline

\_\_\_\_\%

Calculate Probability of $3$ : Step $1$ : Calculate the probability of picking a $3$ from the set \{ $1, 2, 3, 4$ \}. $\newline$ The probability of picking a $3$ is $1$ out of $4$ , so it's $\frac{1}{4}$ .
Update Set After First Pick: Step $2$ : After picking one $3$ , the set becomes \{ $1, 2, 4\}. The probability of picking a$ $3$ $again from this set is$ $0$ $, since there are no$ $3$ $s left.
Multiply Probabilities: Step \(3\): Multiply the probabilities of the two events.\(\newline\)Probability of picking first \(3\): \(\frac{1}{4}\)\(\newline\)Probability of picking second \(3\): \(0\)\(\newline\)Total probability = \(\frac{1}{4} \times 0 = 0\)

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Question

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Question

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\newline

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\newline

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\newline

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\newline

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\newline

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