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You pick a card at random, put it back, and then pick another card at random.\newline234234 \newlineWhat is the probability of picking a 44 and then picking a 44?\newlineWrite your answer as a fraction or whole number.\newline____\_\_\_\_

Full solution

Q. You pick a card at random, put it back, and then pick another card at random.\newline234234 \newlineWhat is the probability of picking a 44 and then picking a 44?\newlineWrite your answer as a fraction or whole number.\newline____\_\_\_\_
  1. Counting Fours in Deck: First, let's figure out how many 44s are in a deck of cards. There are 44 suits, and each suit has one 44 card, so there are 44 fours in a deck of 5252 cards.
  2. Calculate First Draw Probability: Now, calculate the probability of picking a 44 on the first draw. The probability is the number of favorable outcomes (picking a 44) divided by the total number of outcomes (total cards). So, it's 452\frac{4}{52}, which simplifies to 113\frac{1}{13}.
  3. Calculate Second Draw Probability: Since the card is put back in the deck, the total number of cards and the number of 44s remain the same for the second draw. So, the probability of picking another 44 is also 113\frac{1}{13}.
  4. Find Probability of Both Events: To find the probability of both events happening (picking a 44 and then picking another 44), multiply the probabilities of the individual events. So, it's 113×113=1169\frac{1}{13} \times \frac{1}{13} = \frac{1}{169}.

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