You invested $7,500 in a savings account, and after 8 years, the balance grew to $12,282.50. The interest is compounded annually. What is the annual interest rate? Use the formula A=P(1+nr)nt, where A is the balance (final amount), P is the principal (starting amount), r is the interest rate expressed as a decimal, n is the number of times per year that the interest is compounded, and t is the time in years. Round your answer to the nearest tenth.
Q. You invested $7,500 in a savings account, and after 8 years, the balance grew to $12,282.50. The interest is compounded annually. What is the annual interest rate? Use the formula A=P(1+nr)nt, where A is the balance (final amount), P is the principal (starting amount), r is the interest rate expressed as a decimal, n is the number of times per year that the interest is compounded, and t is the time in years. Round your answer to the nearest tenth.
Given Values: We have: A = $12,282.50, P = $7,500, t = 8 \text{ years}, n = 1 \text{ (compounded annually)}. Formula: A = P\left(1 + \frac{r}{n}\right)^{nt}
Substitute into Formula: Substitute the values into the formula: 12,282.50=7,500(1+1r)1⋅8
Simplify Equation: Simplify the equation: 12,282.50=7,500(1+r)8
Divide by 7,500: Divide both sides by 7,500: (12,282.50/7,500)=(1+r)81.6376667=(1+r)8
Take 8th Root: Take the 8th root of both sides to solve for (1+r): (1.6376667)(1/8)=1+r1.063=1+r
Solve for (1+r): Subtract 1 from both sides to solve for r: 1.063−1=rr=0.063
Convert to Percentage: Convert r to a percentage: r=0.063imes100r=6.3extextpercent
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