You invested $2,500 in a savings account, and after 6 years, the balance grew to $3,397.50. The interest is compounded annually. What is the annual interest rate? Use the formula A=P(1+nr)nt, where A is the balance (final amount), P is the principal (starting amount), r is the interest rate expressed as a decimal, n is the number of times per year that the interest is compounded, and t is the time in years. Round your answer to the nearest tenth.
Q. You invested $2,500 in a savings account, and after 6 years, the balance grew to $3,397.50. The interest is compounded annually. What is the annual interest rate? Use the formula A=P(1+nr)nt, where A is the balance (final amount), P is the principal (starting amount), r is the interest rate expressed as a decimal, n is the number of times per year that the interest is compounded, and t is the time in years. Round your answer to the nearest tenth.
Identify Given Values: Identify the given values. A = $3,397.50, P = $2,500, t = 6 \text{ years}\, n = 1 \text{ (compounded annually)}
Use Formula A=P(1+nr)nt: Use the formula A=P(1+nr)nt. 3,397.50=2,500(1+r)6
Divide to Isolate (1+r)6: Divide both sides by 2,500 to isolate (1+r)6. 2,5003,397.50=(1+r)61.359=(1+r)6
Take 6th Root: Take the 6th root of both sides to solve for (1+r). (1.359)(1/6)=1+r1.050=1+r
Subtract to Solve for r: Subtract 1 from both sides to solve for r. 1.050−1=rr=0.050
Convert to Percentage: Convert r to a percentage. r=0.050imes100extextpercentr=5.0extextpercent
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