y=(x-5)^(2)+1 (y-5)/(3)=15 If (x,y) is a solution to the system of equations shown and x 0, what is the value of x ?

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y=(x-5)^(2)+1  (y-5)/(3)=15 If  (x,y) is a solution to the system of equations shown and  x > 0, what is the value of  x ?

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Given Equations: We are given two equations: 1. y = (x - 5)² + 1 2. (y - 5)/3 = 15 We need to find the value of x when x > 0. First, let's solve the second equation for y.Solving Second Equation: Multiply both sides of the second equation by 3 to isolate y. (y - 5) = 15 * 3 y - 5 = 45 Now, add 5 to both sides to solve for y. y = 45 + 5 y = 50 We have found the value of y.Substitute and Solve: Now that we have the value of y, we can substitute it into the first equation to solve for x. Substitute y = 50 into the first equation: 50 = (x - 5)² + 1Isolate Squared Term: Subtract 1 from both sides to isolate the squared term. 50 - 1 = (x - 5)² 49 = (x - 5)² Now we need to find the square root of both sides to solve for x.Find Positive Solution: Taking the square root of both sides gives us two possible solutions for x - 5: x - 5 = √49 or x - 5 = -√49 x - 5 = 7 or x - 5 = -7 Since we are looking for the value of x where x > 0, we will only consider the positive solution.Final Solution: Add 5 to both sides of the equation to solve for x: x = 7 + 5 x = 12 We have found the value of x that satisfies the system of equations and the condition x > 0.

$y=(x-5)^{2}+1$ $\newline$ $(y-5)/3=15$ $\newline$ If $\newline$ $(x,y)$ is a solution to the system of equations shown and $\newline$ x > 0, what is the value of $\newline$ $x$ ?

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$y=(x-5)^{2}+1$ $\newline$ $(y-5)/3=15$ $\newline$ If $\newline$ $(x,y)$ is a solution to the system of equations shown and $\newline$ x > 0, what is the value of $\newline$ $x$ ?