Q. For the following set of data, find the sample standard deviation, to the nearest thousandth.70,39,114,39,52,108,101
List data set: List the given data set.The data set provided is: 70,39,114,39,52,108,101.
Calculate mean: Calculate the mean (average) of the data set.To find the mean, sum all the data points and divide by the number of data points.Mean = (70+39+114+39+52+108+101)/7Mean = 523/7Mean ≈74.714
Calculate deviations: Calculate the deviations from the mean for each data point. This involves subtracting the mean from each data point. Deviations: (70−74.714), (39−74.714), (114−74.714), (39−74.714), (52−74.714), (108−74.714), (101−74.714)
Square deviations: Square each deviation to get the squared deviations.Squared deviations: (70−74.714)2, (39−74.714)2, (114−74.714)2, (39−74.714)2, (52−74.714)2, (108−74.714)2, (101−74.714)2
Sum squared deviations: Sum the squared deviations.Sum of squared deviations = (70−74.714)2+(39−74.714)2+(114−74.714)2+(39−74.714)2+(52−74.714)2+(108−74.714)2+(101−74.714)2Sum of squared deviations ≈22.449+1277.571+1538.449+1277.571+517.571+1111.449+689.571Sum of squared deviations ≈5434.631
Calculate variance: Divide the sum of squared deviations by the sample size minus one to get the variance.Since we have 7 data points, we divide by 6 (n−1).Variance = 5434.631/6Variance ≈905.772
Find standard deviation: Take the square root of the variance to find the sample standard deviation.Sample standard deviation = 905.772Sample standard deviation ≈30.096
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