Q. yy=6x−30=x2−18x+114 If (a,b) is the solution to the system of equations shown, what is the value of b? □
Set Equations Equal: Given the system of equations:1) y=6x−302) y=x2−18x+114To find the value of b, we need to solve the system of equations. We can do this by setting the two expressions for y equal to each other and solving for x.
Move Terms to Solve: Set the two equations equal to each other:6x−30=x2−18x+114Now, we will move all terms to one side to solve for x.
Rearrange and Combine: Rearrange the equation:x2−18x+114−6x+30=0Combine like terms:x2−24x+144=0This is a quadratic equation in standard form.
Factor Quadratic Equation: Factor the quadratic equation:(x−12)(x−12)=0This gives us a repeated root, meaning x has one value where the equation is true.
Solve for x: Solve for x:x−12=0x=12We have found the value of x that satisfies both equations.
Substitute x into Equation: Now that we have the value of x, we can substitute it back into either of the original equations to find the value of y, which corresponds to b in the solution (a,b). Let's substitute x into the first equation: y=6x−30
Calculate Value of y: Substitute x=12 into the equation:y=6(12)−30Calculate the value of y:y=72−30y=42We have found the value of y, which is the value of b in the solution (a,b).
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