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yamp;=6x30yamp;=x218x+114\begin{align*} y &= 6x-30 \\ y &= x^{2}-18x+114 \end{align*} \newline If (a,b)(a,b) is the solution to the system of equations shown, what is the value of bb? \newline\square

Full solution

Q. y=6x30y=x218x+114\begin{align*} y &= 6x-30 \\ y &= x^{2}-18x+114 \end{align*} \newline If (a,b)(a,b) is the solution to the system of equations shown, what is the value of bb? \newline\square
  1. Set Equations Equal: Given the system of equations:\newline11) y=6x30y = 6x - 30\newline22) y=x218x+114y = x^2 - 18x + 114\newlineTo find the value of bb, we need to solve the system of equations. We can do this by setting the two expressions for yy equal to each other and solving for xx.
  2. Move Terms to Solve: Set the two equations equal to each other:\newline6x30=x218x+1146x - 30 = x^2 - 18x + 114\newlineNow, we will move all terms to one side to solve for xx.
  3. Rearrange and Combine: Rearrange the equation:\newlinex218x+1146x+30=0x^2 - 18x + 114 - 6x + 30 = 0\newlineCombine like terms:\newlinex224x+144=0x^2 - 24x + 144 = 0\newlineThis is a quadratic equation in standard form.
  4. Factor Quadratic Equation: Factor the quadratic equation:\newline(x12)(x12)=0(x - 12)(x - 12) = 0\newlineThis gives us a repeated root, meaning xx has one value where the equation is true.
  5. Solve for x: Solve for x:\newlinex12=0x - 12 = 0\newlinex=12x = 12\newlineWe have found the value of xx that satisfies both equations.
  6. Substitute xx into Equation: Now that we have the value of xx, we can substitute it back into either of the original equations to find the value of yy, which corresponds to bb in the solution (a,b)(a,b). Let's substitute xx into the first equation: y=6x30y = 6x - 30
  7. Calculate Value of y: Substitute x=12x = 12 into the equation:\newliney=6(12)30y = 6(12) - 30\newlineCalculate the value of y:\newliney=7230y = 72 - 30\newliney=42y = 42\newlineWe have found the value of y, which is the value of bb in the solution (a,b)(a,b).

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