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y=5(x−2)2−4y=5(x-2)^2-4

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Composition of linear and quadratic functions: find a valueright chevron icon

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Q. y=5(x−2)2−4y=5(x-2)^2-4
  1. Substitute xx with 00: To find the value of yy when xx equals 00, we need to substitute xx with 00 in the equation y=5(x−2)2−4y=5(x-2)^2-4.\newlineCalculation: y=5(0−2)2−4y = 5(0-2)^2 - 4
  2. Calculate inside parentheses: Calculate the value inside the parentheses first: (0−2)2(0-2)^2.\newlineCalculation: (0−2)2=(−2)2=4(0-2)^2 = (-2)^2 = 4
  3. Multiply by 55: Now, multiply the result by 55, as indicated by the equation.\newlineCalculation: 5×4=205 \times 4 = 20
  4. Subtract 44: Finally, subtract 44 from the result obtained in the previous step to find the value of yy.\newlineCalculation: 20−4=1620 - 4 = 16

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