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Find (fg)(x)(f \circ g)(x).\newlinef(x)=x2+5f(x) = x^2 + 5\newlineg(x)=4xg(x) = 4x\newlineWrite your answer as a polynomial in simplest form.\newline(fg)(x)=(f \circ g)(x) = ______

Full solution

Q. Find (fg)(x)(f \circ g)(x).\newlinef(x)=x2+5f(x) = x^2 + 5\newlineg(x)=4xg(x) = 4x\newlineWrite your answer as a polynomial in simplest form.\newline(fg)(x)=(f \circ g)(x) = ______
  1. Substitute g(x)g(x) into f(x)f(x): Now, let's substitute g(x)g(x) into f(x)f(x).f(g(x))=f(4x)=(4x)2+5f(g(x)) = f(4x) = (4x)^2 + 5.
  2. Simplify the equation: Next, we simplify the equation. f(g(x))=16x2+5f(g(x)) = 16x^2 + 5.

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