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y-3=2(x+1)
Complete the missing value in the solution to the equation.

(-1,◻)

$y-3=2(x+1)$ $\newline$ Complete the missing value in the solution to the equation. $\newline$ $(-1, \square)$

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Does (x, y) satisfy the linear equation?

Full solution

Q.

y-3=2(x+1)

\newline

Complete the missing value in the solution to the equation.

\newline

(-1, \square)

Substitute x-value: Substitute the given $x$ -value into the equation to find the corresponding $y$ -value. $\newline$ We are given the point $(-1,\square)$ , which means $x = -1$ . We need to substitute $x = -1$ into the equation $y - 3 = 2(x + 1)$ to find the $y$ -value. $\newline$ $y - 3 = 2(-1 + 1)$
Simplify equation: Simplify the equation by performing the operations inside the parentheses. $\newline$ $2(-1 + 1) = 2(0) = 0$ $\newline$ Now we have $y - 3 = 0$
Solve for y: Solve for y by adding $3$ to both sides of the equation. $\newline$ $y - 3 + 3 = 0 + 3$ $\newline$ $y = 3$
Check solution: Check the solution by substituting the found $y$ -value back into the original equation. $\newline$ Substitute $y = 3$ and $x = -1$ into the equation $y - 3 = 2(x + 1)$ to verify the solution. $\newline$ $3 - 3 = 2(-1 + 1)$ $\newline$ $0 = 2(0)$ $\newline$ $0 = 0$ $\newline$ This confirms that $y = 3$ is the correct solution for $x = -1$ .

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