Line p has an equation of y=−8x+6. Line q, which is perpendicular to line p, includes the point (2,−2). What is the equation of line q?Write the equation in slope-intercept form.
Q. Line p has an equation of y=−8x+6. Line q, which is perpendicular to line p, includes the point (2,−2). What is the equation of line q?Write the equation in slope-intercept form.
Find Slope of Line p: Line p has a slope of −8, as we can see from its equation y=−8x+6. Since line q is perpendicular to line p, we need to find the slope of line q, which will be the negative reciprocal of the slope of line p.
Determine Slope of Line q: The negative reciprocal of −8 is 81. Therefore, the slope of line q is 81.
Calculate Y-Intercept of Line q: Now we need to find the y-intercept of line q. We know that line q passes through the point (2,−2) and has a slope of 81. We can use the point-slope form of the equation of a line to find the y-intercept. The point-slope form is y−y1=m(x−x1), where m is the slope and (x1,y1) is a point on the line.
Apply Point-Slope Form: Plugging in the slope and the point (2,−2) into the point-slope form, we get y−(−2)=81(x−2). Simplifying this, we get y+2=81x−41.
Isolate y in Equation: To get the equation in slope-intercept form, we need to isolate y. Subtracting 2 from both sides of the equation, we get y=81x−41−2.
Simplify Final Equation: Simplifying the equation further, we combine the constant terms −41 and −2. Since −2 is the same as −48, we get y=81x−41−48, which simplifies to y=81x−49.
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