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y=2(x−3)2+5y=2(x-3)^2+5

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Composition of linear and quadratic functions: find a valueright chevron icon

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Q. y=2(x−3)2+5y=2(x-3)^2+5
  1. Substitute xx with 00: To find the value of yy when xx equals 00, we need to substitute xx with 00 in the equation y=2(x−3)2+5y=2(x-3)^2+5.\newlineCalculation: y=2(0−3)2+5y = 2(0-3)^2 + 5
  2. Calculate value inside parentheses: Calculate the value inside the parentheses (0−3)(0-3).\newlineCalculation: 0−3=−30 - 3 = -3
  3. Square the result: Square the result of the previous step (−3)2(-3)^2.\newlineCalculation: (−3)2=9(-3)^2 = 9
  4. Multiply by 22: Multiply the squared result by 22, according to the equation.\newlineCalculation: 2×9=182 \times 9 = 18
  5. Add 55 to find y: Add 55 to the result of the previous multiplication to find the value of yy.\newlineCalculation: 18+5=2318 + 5 = 23

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