x(x−a)−b(a+b)=0In the given equation, a and b are constants. What are the solutions to the equation?Choose 1 answer:(A) x=−b and x=(a−b)(B) x=−b and x=(a+b)(C) x=a and x=(a−b)(D) x=a and x=(a+b)
Q. x(x−a)−b(a+b)=0In the given equation, a and b are constants. What are the solutions to the equation?Choose 1 answer:(A) x=−b and x=(a−b)(B) x=−b and x=(a+b)(C) x=a and x=(a−b)(D) x=a and x=(a+b)
Expand and Simplify Equation: First, we need to expand the equation to see if it can be factored easily.x(x−a)−b(a+b)=0x2−ax−ab−b2=0
Find Factors of Quadratic Equation: Now, we look for factors of the quadratic equation that could give us the solutions for x. We need to find two numbers that multiply to give −ab−b2 and add up to give −a.
Analyze Factorization and Sum: We notice that the two numbers that satisfy these conditions are −b and a−b because:(−b)⋅(a−b)=−ab+b2(−b)+(a−b)=−b+a−b=a−2bHowever, we need the sum to be −a, not a−2b. This indicates that we might have made a mistake in our factorization or that the equation does not factor in the way we expected.
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