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XX is a normally distributed random variable with mean 4343 and standard deviation 1818. What is the probability that XX is between 2525 and 6161? Use the 0.680.950.9970.68-0.95-0.997 rule and write your answer as a decimal. Round to the nearest thousandth if necessary.

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Q. XX is a normally distributed random variable with mean 4343 and standard deviation 1818. What is the probability that XX is between 2525 and 6161? Use the 0.680.950.9970.68-0.95-0.997 rule and write your answer as a decimal. Round to the nearest thousandth if necessary.
  1. Mean and SD given: Mean (μ\mu) is 4343 and standard deviation (σ\sigma) is 1818. We need to find P(25 < X < 61).
  2. Calculate Z-score for X=25X=25: For X=25X = 25, calculate the Z-score: Z=Xμσ=254318=1818=1Z = \frac{X - \mu}{\sigma} = \frac{25 - 43}{18} = \frac{-18}{18} = -1.
  3. Calculate Z-score for X=61X=61: For X=61X = 61, calculate the Z-score: Z=Xμσ=614318=1818=1Z = \frac{X - \mu}{\sigma} = \frac{61 - 43}{18} = \frac{18}{18} = 1.
  4. Find probability within one SD: The Z-scores for X=25X = 25 and X=61X = 61 are 1-1 and 11, respectively. This corresponds to the probability within one standard deviation of the mean, which is 0.680.68 according to the 0.680.950.9970.68-0.95-0.997 rule.
  5. Calculate probability for XX between 2525 and 6161: Therefore, the probability that XX is between 2525 and 6161 is approximately 0.680.68.

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