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Xóchitl, who has already warmed up, immediately starts to pedal at a rate of 
18(km)/(h) on a stationary bike.
She sees that her friend Cowessess has already pedaled. 12 minutes at an average rate of 
10(km)/(h).
Assuming Cowessess's rate stays the same, how long would Xóchitl have to pedal to catch up to Cowessess's distance?

Xóchitl, who has already warmed up, immediately starts to pedal at a rate of 18kmh 18 \frac{\mathrm{km}}{\mathrm{h}} on a stationary bike.\newlineShe sees that her friend Cowessess has already pedaled. 1212 minutes at an average rate of 10kmh 10 \frac{\mathrm{km}}{\mathrm{h}} .\newlineAssuming Cowessess's rate stays the same, how long would Xóchitl have to pedal to catch up to Cowessess's distance?

Full solution

Q. Xóchitl, who has already warmed up, immediately starts to pedal at a rate of 18kmh 18 \frac{\mathrm{km}}{\mathrm{h}} on a stationary bike.\newlineShe sees that her friend Cowessess has already pedaled. 1212 minutes at an average rate of 10kmh 10 \frac{\mathrm{km}}{\mathrm{h}} .\newlineAssuming Cowessess's rate stays the same, how long would Xóchitl have to pedal to catch up to Cowessess's distance?
  1. Calculate Distance Covered: Calculate the distance Cowessess has already covered.\newlineCowessess has pedaled for 1212 minutes at a rate of 10km/h10\,\text{km/h}. To find the distance, we convert the time to hours and multiply by the rate.\newline1212 minutes =1260= \frac{12}{60} hours =0.2= 0.2 hours\newlineDistance == Rate ×\times Time\newlineDistance =10km/h×0.2hours= 10\,\text{km/h} \times 0.2\,\text{hours}\newlineDistance =2km= 2\,\text{km}
  2. Determine Time for Xóchitl: Determine how long it will take Xóchitl to cover the same distance.\newlineXóchitl is pedaling at a rate of 18km/h18 \, \text{km/h}. To find the time it takes to cover 2km2 \, \text{km}, we divide the distance by Xóchitl's rate.\newlineTime = Distance / Rate\newlineTime = 2km/18km/h2 \, \text{km} / 18 \, \text{km/h}\newlineTime = 1/9hours1/9 \, \text{hours}\newlineTo convert this time into minutes, we multiply by 6060.\newlineTime in minutes = (1/9)×60(1/9) \times 60\newlineTime in minutes = 6.6666.666\ldots minutes\newlineXóchitl would need to pedal for approximately 6.676.67 minutes to cover 2km2 \, \text{km}.

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