x^(2)y(2xy^(2)-7xy+5x-4y)

Distribute x^(2)y: Distribute x^(2)y across the terms inside the parentheses (2xy^(2)-7xy+5x-4y). To distribute, multiply x^(2)y by each term inside the parentheses.Multiply 2xy^(2): Multiply x^(2)y by the first term 2xy^(2). x^(2)y * 2xy^(2) = 2x^(3)y^(3)Multiply -7xy: Multiply x^(2)y by the second term -7xy. x^(2)y * -7xy = -7x^(3)y^(2)Multiply 5x: Multiply x^(2)y by the third term 5x. x^(2)y * 5x = 5x^(3)yMultiply -4y: Multiply x^(2)y by the fourth term -4y. x^(2)y * -4y = -4x^(2)y^(2)Combine results: Combine the results from steps 2 to 5 to get the final expression. 2x^(3)y^(3) - 7x^(3)y^(2) + 5x^(3)y - 4x^(2)y^(2)

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$x^{2} y\left(2 x y^{2}-7 x y+5 x-4 y\right)$

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Algebra 2

Quadratic equation with complex roots

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x^{2} y\left(2 x y^{2}-7 x y+5 x-4 y\right)

Distribute $x^{2}y$ : Distribute $x^{2}y$ across the terms inside the parentheses $(2xy^{2}-7xy+5x-4y)$ . To distribute, multiply $x^{2}y$ by each term inside the parentheses.
Multiply $2xy^{2}$ : Multiply $x^{2}y$ by the first term $2xy^{2}$ . $\newline$ $x^{2}y \times 2xy^{2} = 2x^{3}y^{3}$
Multiply $-7xy$ : Multiply $x^{2}y$ by the second term $-7xy$ . $x^{2}y \times -7xy = -7x^{3}y^{2}$
Multiply $5x$ : Multiply $x^{2}y$ by the third term $5x$ . $\newline$ $x^{2}y \times 5x = 5x^{3}y$
Multiply $-4y$ : Multiply $x^{2}y$ by the fourth term $-4y$ . $\newline$ $x^{2}y \times -4y = -4x^{2}y^{2}$
Combine results: Combine the results from steps $2$ to $5$ to get the final expression. $2x^{3}y^{3} - 7x^{3}y^{2} + 5x^{3}y - 4x^{2}y^{2}$