Write the quadratic equation in standard form: -x^(2)-8x-15=4x^(2) Answer:

Simplify terms on both sides: Now, we simplify the terms on both sides of the equation. 0x^2 - 8x - 15 = x^2 Since 0x^2 is just 0, it disappears from the equation, and we are left with: -8x - 15 = x^2Write equation in standard form: Next, we need to write the equation in standard form, which is ax^2 + bx + c = 0. To do this, we subtract x^2 from both sides to bring all terms to the left side of the equation. -8x - 15 - x^2 = x^2 - x^2Equation in standard form: After subtracting x^2 from both sides, we get the equation in standard form: -x^2 - 8x - 15 = 0 This is the quadratic equation in standard form.

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Write the quadratic equation in standard form:

-x^(2)-8x-15=4x^(2)
Answer:

Write the quadratic equation in standard form: $\newline$ $-x^{2}-8 x-15=4 x^{2}$ $\newline$ Answer:

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Algebra 2

Quadratic equation with complex roots

Full solution

Q. Write the quadratic equation in standard form:

\newline

-x^{2}-8 x-15=4 x^{2}

\newline

Answer:

Simplify terms on both sides: Now, we simplify the terms on both sides of the equation. $\newline$ $0x^2 - 8x - 15 = x^2$ $\newline$ Since $0x^2$ is just $0$ , it disappears from the equation, and we are left with: $\newline$ $-8x - 15 = x^2$
Write equation in standard form: Next, we need to write the equation in standard form, which is $ax^2 + bx + c = 0$ . To do this, we subtract $x^2$ from both sides to bring all terms to the left side of the equation. $-8x - 15 - x^2 = x^2 - x^2$
Equation in standard form: After subtracting $x^2$ from both sides, we get the equation in standard form: $\newline$ $-x^2 - 8x - 15 = 0$ $\newline$ This is the quadratic equation in standard form.