Write the quadratic equation in standard form: -x^(2)-6=-6x Answer:

Add 6x to both sides: First, add 6x to both sides of the equation to move the term involving x to the left side. -x^2 - 6 + 6x = -6x + 6x This simplifies to: -x^2 + 6x - 6 = 0Multiply by -1: Now, we have the quadratic equation in standard form. However, it is customary to write the x^2 term as positive. To do this, we can multiply the entire equation by -1. Multiplying by -1, we get: (-1)(-x^2 + 6x - 6) = (-1)(0) This simplifies to: x^2 - 6x + 6 = 0Final standard form: We have now successfully written the quadratic equation in standard form. The final standard form of the quadratic equation is x^2 - 6x + 6 = 0.

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Write the quadratic equation in standard form:

-x^(2)-6=-6x
Answer:

Write the quadratic equation in standard form: $\newline$ $-x^{2}-6=-6 x$ $\newline$ Answer:

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Algebra 2

Quadratic equation with complex roots

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Q. Write the quadratic equation in standard form:

\newline

-x^{2}-6=-6 x

\newline

Answer:

Add $6x$ to both sides: First, add $6x$ to both sides of the equation to move the term involving $x$ to the left side. $\newline$ $-x^2 - 6 + 6x = -6x + 6x$ $\newline$ This simplifies to: $\newline$ $-x^2 + 6x - 6 = 0$
Multiply by $-1$ : Now, we have the quadratic equation in standard form. However, it is customary to write the $x^2$ term as positive. To do this, we can multiply the entire equation by $-1$ . $\newline$ Multiplying by $-1$ , we get: $\newline$ $(-1)(-x^2 + 6x - 6) = (-1)(0)$ $\newline$ This simplifies to: $\newline$ $x^2 - 6x + 6 = 0$
Final standard form: We have now successfully written the quadratic equation in standard form. The final standard form of the quadratic equation is $x^2 - 6x + 6 = 0$ .